Question

我有这样的查询：

SELECT id, @RowNumber = ROW_NUMBER() OVER (ORDER BY id) as 'number' 
FROM WaitList 
WHERE email = @Email

然而我收到错误：

Incorrect syntax near the keyword 'as'.

我要做的是将ROW_NUMBER（）分配给变量。

我真的需要从WaitList表中获取行号。

我可以将结果放在变量表中，然后通过选择“数字”来获取行号吗？

Answer 1

您的代码看起来像SQL Server。您无法分配变量和返回具有相同查询的结果集：

SELECT id, ROW_NUMBER() OVER (ORDER BY id) as number
FROM WaitList 
WHERE email = @Email;

将值赋值给变量并不是很有意义。如果你想要，比如匹配行的总数，那么使用聚合函数：

select @cnt = count(*)
from waitlist
where email = @email;

Answer 2

如果您想要具有匹配电子邮件地址的行号，但该表实际上没有行号，那么您应创建一个CTE来分配行号，然后从中选择特定行......这样的事情：

WITH NumberedRows AS (
    SELECT [id], [email], ROW_NUMBER() OVER (ORDER BY id) as [Number] 
    FROM WaitList 
)
SELECT @RowNumber = Number
FROM NumberedRows
WHERE email = @Email

请注意，如果在此之前有SELECT语句，则需要确保使用分号终止SELECT语句（或其他SQL语句）。或者，如果您愿意，您可以在WITH前加上一个分号，例如＆＃34 ;; WITH ...＆＃34;

Answer 3

 select a.id , a.number 
 from
 (SELECT id, ROW_NUMBER() OVER (ORDER BY id) as number
 FROM WaitList 
 WHERE email = @Email) a

Answer 4

SELECT id, ROW_NUMBER() OVER ( ORDER BY id) as number
FROM WaitList 
WHERE email = @Email;

SQL不正确的语法接近将输出分配给变量

4 个答案: