Question

以下查询将显示已在“book”表中复制的所有Dewey Decimal数字：

SELECT dewey_number, 
 COUNT(dewey_number) AS NumOccurrences
FROM book
GROUP BY dewey_number
HAVING ( COUNT(dewey_number) > 1 )

但是，我想要做的是让我的查询显示与重复条目相关联的作者的名称（“book”表和“author”表通过“author_id”连接）。换句话说，上面的查询将产生以下结果：

dewey_number | NumOccurrences
------------------------------
5000         | 2
9090         | 3

我希望显示的结果类似于以下内容：

author_last_name | dewey_number | NumOccurrences
-------------------------------------------------
Smith            | 5000         | 2
Jones            | 5000         | 2
Jackson          | 9090         | 3
Johnson          | 9090         | 3
Jeffers          | 9090         | 3

非常感谢您提供的任何帮助。并且，如果它发挥作用，我正在使用Postgresql DB。

更新：请注意“author_last_name”不在“book”表中。

Answer 1

嵌套查询可以完成这项工作。

SELECT author_last_name, dewey_number, NumOccurrences
FROM author INNER JOIN
     ( SELECT author_id, dewey_number,  COUNT(dewey_number) AS NumOccurrences
        FROM book
        GROUP BY author_id, dewey_number
        HAVING ( COUNT(dewey_number) > 1 ) ) AS duplicates
ON author.id = duplicates.author_id

（我不知道这是否是达到你想要的最快方式。）

更新：这是我的数据

SELECT * FROM author;
 id | author_last_name 
----+------------------
  1 | Fowler
  2 | Knuth
  3 | Lang

SELECT * FROM book;
 id | author_id | dewey_number |         title          
----+-----------+--------------+------------------------
  1 |         1 |          600 | Refactoring
  2 |         1 |          600 | Refactoring
  3 |         1 |          600 | Analysis Patterns
  4 |         2 |          600 | TAOCP vol. 1
  5 |         2 |          600 | TAOCP vol. 1
  6 |         2 |          600 | TAOCP vol. 2
  7 |         3 |          500 | Algebra
  8 |         3 |          500 | Undergraduate Analysis
  9 |         1 |          600 | Refactoring
 10 |         2 |          500 | Concrete Mathematics
 11 |         2 |          500 | Concrete Mathematics
 12 |         2 |          500 | Concrete Mathematics

以上是上述查询的结果：

 author_last_name | dewey_number | numoccurrences 
------------------+--------------+----------------
 Fowler           |          600 |              4
 Knuth            |          600 |              3
 Knuth            |          500 |              3
 Lang             |          500 |              2

Answer 2

你可能想要这个

SELECT dewey_number, author_last_name,
 COUNT(dewey_number) AS NumOccurrences
FROM book
GROUP BY dewey_number,author_last_name
HAVING ( COUNT(dewey_number) > 1 )

Answer 3

SELECT dewey_number, author_last_name,
       COUNT(dewey_number) AS NumOccurrences
FROM book
JOIN author USING (author_id)
GROUP BY dewey_number,author_last_name
HAVING COUNT(dewey_number) > 1

如果book.author_id可以为null，则将连接更改为：

LEFT OUTER JOIN author USING (author_id)

如果author_id列在每个表中都有不同的名称，那么您不能使用USING，而是使用ON：

JOIN author ON author.id = book.author_id

或

LEFT OUTER JOIN author ON author.id = book.author_id

Answer 4

select author_name,dewey_number,Num_of_occur
from author a,(select author_id,dewey_number,count(dewey_number) Num_of_occur
                from   book
                group by author_id,dewey_number
                having count(dewey_number) > 1) dup
where a.author_id = dup.author_id

Answer 5

我找到的最简单有效的方法如下所示：

SELECT
    p.id
    , p.full_name
    , (SELECT count(id) FROM tbl_documents as t where t.person_id = p.id) as rows
FROM tbl_people as p
WHERE 
    p.id 
IN (SELECT d.person_id FROM tbl_documents as d 
    GROUP BY d.person_id HAVING count(d.id) > 1) 
ORDER BY 
    p.full_name

Answer 6

select * from author
dewey_number    author_last_name
1   Ramu
2   Rajes
1   Samy
1   Ramu

select * from book
authorid    dewey_number
1   1
2   1

select a.dewey_number,a.author_last_name,count(a.dewey_number) from author a
where a.dewey_number in (
select b.dewey_number from book b )
group by a.dewey_number,a.author_last_name

dewey_number    author_last_name    (No column name)
1   Ramu    2
1   Samy    1

如何在数据库表中找到重复的条目？

6 个答案: