我发现使用XML中的属性和嵌套元素很难。
如果我只想提取具有属性Phone
的{{1}}元素并在一行中打印地址,我该如何在LINQ中执行此操作?
我想生成如下输出:
Type="Mobile"
请帮忙,下面是我的示例xml文件
332-899-5678 | 123 Main, St Mercer Island, WA 68042
答案 0 :(得分:3)
string xml = @"<Contacts>
<Contact>
<Name>Patrick Hines</Name>
<Phone Type=""Home"">206-555-0144</Phone>
<Phone Type=""Work"">425-555-0145</Phone>
<Phone Type=""Mobile"">332-899-5678</Phone>
<Address>
<Street1>123 Main St</Street1>
<City>Mercer Island</City>
<State>WA</State>
<Postal>68042</Postal>
</Address>
</Contact>
<Contact>
<Name>Dorothy Lee</Name>
<Phone Type=""Home"">910-555-1212</Phone>
<Phone Type=""Work"">336-555-0123</Phone>
<Phone Type=""Mobile"">336-555-0005</Phone>
<Address>
<Street1>16 Friar Duck Ln</Street1>
<City>Greensboro</City>
<State>NC</State>
<Postal>27410</Postal>
</Address>
</Contact>
</Contacts>";
XDocument document = XDocument.Parse(xml);
var query = from contact in document.Descendants("Contact")
let address = contact.Element("Address")
select new
{
Name = contact.Element("Name").Value,
MobilePhone = contact.Elements("Phone").Where(ele => ele.Attribute("Type").Value == "Mobile").First().Value,
Street1 = address.Element("Street1").Value,
City = address.Element("City").Value,
State = address.Element("State").Value,
Postal = address.Element("Postal").Value
};
foreach (var item in query)
{
Console.WriteLine("{0} | {1}, {2}, {3} {4}", item.MobilePhone, item.Street1, item.City, item.State, item.Postal);
}
答案 1 :(得分:2)
也许是这样的:
var rows =
from contact in root.Elements("Contact")
let phone = (string)contact.Elements("Phone").FirstOrDefault(
(string)p => p.Attribute("Type") == "Mobile")
let addr = contact.Element("Address")
select phone + " | " +
(string)addr.Element("Street1") + " | " +
(string)addr.Element("City") + " | " +
...