如何在LINQ中查询此XML?

时间:2010-12-05 15:54:04

标签: c# xml linq

我发现使用XML中的属性和嵌套元素很难。 如果我只想提取具有属性Phone的{​​{1}}元素并在一行中打印地址,我该如何在LINQ中执行此操作?

我想生成如下输出:

Type="Mobile"

请帮忙,下面是我的示例xml文件

332-899-5678 | 123 Main, St Mercer Island, WA 68042

2 个答案:

答案 0 :(得分:3)

string xml = @"<Contacts> 
    <Contact> 
    <Name>Patrick Hines</Name> 
    <Phone Type=""Home"">206-555-0144</Phone> 
    <Phone Type=""Work"">425-555-0145</Phone> 
    <Phone Type=""Mobile"">332-899-5678</Phone> 
    <Address> 
        <Street1>123 Main St</Street1> 
        <City>Mercer Island</City> 
        <State>WA</State> 
        <Postal>68042</Postal> 
    </Address> 
    </Contact> 
    <Contact> 
    <Name>Dorothy Lee</Name> 
    <Phone Type=""Home"">910-555-1212</Phone> 
    <Phone Type=""Work"">336-555-0123</Phone> 
    <Phone Type=""Mobile"">336-555-0005</Phone> 
    <Address> 
        <Street1>16 Friar Duck Ln</Street1> 
        <City>Greensboro</City> 
        <State>NC</State> 
        <Postal>27410</Postal> 
    </Address> 
    </Contact>
</Contacts>";

XDocument document = XDocument.Parse(xml);
var query = from contact in document.Descendants("Contact")
            let address = contact.Element("Address")
            select new
            {
                Name = contact.Element("Name").Value,
                MobilePhone = contact.Elements("Phone").Where(ele => ele.Attribute("Type").Value == "Mobile").First().Value,
                Street1 = address.Element("Street1").Value,
                City = address.Element("City").Value,
                State = address.Element("State").Value,
                Postal = address.Element("Postal").Value
            };

foreach (var item in query)
{
    Console.WriteLine("{0} | {1}, {2}, {3} {4}", item.MobilePhone, item.Street1, item.City, item.State, item.Postal);
}

答案 1 :(得分:2)

也许是这样的:

var rows =
    from contact in root.Elements("Contact")
    let phone = (string)contact.Elements("Phone").FirstOrDefault(
          (string)p => p.Attribute("Type") == "Mobile")
    let addr = contact.Element("Address")
    select phone + " | " +
         (string)addr.Element("Street1") + " | " +
         (string)addr.Element("City") + " | " +
         ...