Question

好的，我试图制作一个简单的程序，读取当天销售的比萨饼的数量，然后让用户输入当天销售的披萨类型（有了这个，我需要使用Split （）用户输入）。

我在填充jagged数组的列时遇到问题。

现在，我可以得到我只有1个披萨出售的工作，但除此之外的任何事情都没有考虑到当天销售的比萨饼类型（列值）的用户输入。它没有将用户输入作为单独的项目读取，因此一旦我输入，它就会转到下一行，就像它在等待数据而不是继续前进一样。（因为我测试了一天，所以一旦读入用户输入就会结束程序。）

我不太确定我的问题出在哪里，我的循环放入我的列值，但是我觉得它有一些东西用于读取用户输入并将其放在锯齿状数组的列中。任何帮助都会很棒。

static void Main(string[] args)
    {
        Greeting();
        string[][] pizza = new string[7][];
        GetPizzas(pizza);

    }

    static void Greeting()
    {
        Write("Welcome to Z's Pizza Report!");
    }

    static void GetPizzas(string[][] array)
    {
        int numOfPizza;
        string day;
        for (int r = 0; r < array.Length; r++)
        {
            if (r == 0)
            {
                day = "Monday";
                Write("How many total pizzas were there for {0}? ", day);
                numOfPizza = int.Parse(ReadLine());
                while (numOfPizza < 0)
                {
                    Write("Number cannot be negative. Try Again: ");
                    numOfPizza = int.Parse(ReadLine());
                }

                array[r] = new string[numOfPizza];
                Write("Enter all the pizzas for {0}, seperated by spaces: ", day);

                for (int c = 0; c < array[r].Length; c++)
                {
                    string total = ReadLine();
                    array[c] = total.Split(' ');
                    while (array[r] != array[c])
                    {
                        Write("Input does not match number needed. Try Again: ");
                        total = ReadLine();
                        array[c] = total.Split(' ');
                    }
                }
            }
            else if (r == 1)
            {
                day = "Tuesday";
            }
            else if (r == 2)
            {
                day = "Wednesday";
            }
            else if (r == 3)
            {
                day = "Thursday";
            }
            else if (r == 4)
            {
                day = "Friday";
            }
            else if (r == 5)
            {
                day = "Saturday";
            }
            else
            {
                day = "Sunday";
            }

        }
    }

Answer 1

代码对我来说似乎过于复杂，但是这样做会有帮助吗？哦，请注意我使用内置的DayOfWeek枚举来解析当天的友好名称。这与您的区别在于Sunday是日0。

这行代码将整数转换为枚举，然后获取字符串值：

var dayOfWeek = ((DayOfWeek)i).ToString();

我还添加了一个辅助函数来从用户那里获取一个整数。它接收一个提示字符串，一个错误字符串，一个可选的最小值和一个可选的最大值，然后它会提示用户输入一个整数并且不会返回它们，直到它们输入一个有效值：

static int GetIntFromUser(string prompt, string error, 
    int minValue = int.MinValue, int maxValue = int.MaxValue)
{
    int result;

    if (!string.IsNullOrEmpty(prompt)) Console.Write(prompt);

    while (!int.TryParse(Console.ReadLine(), out result) 
           || result < minValue || result > maxValue)
    {
        if (!string.IsNullOrEmpty(error)) Console.Write(error);
    }

    return result;
}

其余代码如下：

static void Main(string[] args)
{
    var pizzasSold = new string[7][];

    GetPizzas(pizzasSold);

    for (int i = 0; i < pizzasSold.Length; i++)
    {
        var dayOfWeek = ((DayOfWeek)i).ToString();
        Console.WriteLine("You sold {0} pizzas on {1}: {2}", 
            pizzasSold[i].Length, dayOfWeek, string.Join(", ", pizzasSold[i]));
    }

    Console.Write("\nDone!\nPress any key to exit...");
    Console.ReadKey();
}

static void GetPizzas(string[][] array)
{
    for (int r = 0; r < array.Length; r++)
    {
        var dayOfWeek = ((DayOfWeek)r).ToString();

        var numPizzasSold =
                GetIntFromUser($"How many total pizzas were there for {dayOfWeek}? ",
                "Number cannot be negative. Try Again: ", 0);

        Console.Write($"Enter all the pizzas for {dayOfWeek}, seperated by spaces: ");
        var pizzasSold = Console.ReadLine().Split(new[] { ' ' }, 
            StringSplitOptions.RemoveEmptyEntries);

        while (pizzasSold.Length != numPizzasSold)
        {
            Console.Write($"Input does not match number needed. Try Again: ");
            pizzasSold = Console.ReadLine().Split(new[] { ' ' }, 
                StringSplitOptions.RemoveEmptyEntries);
        }

        array[r] = pizzasSold;
    }
}

Answer 2

using System;

namespace ConsoleApp12
{
    class Program
    {
        static void Main(string[] args)
        {
            int[][] n = new int[3][];
            int i;
            n[0] = new int[4];
            n[1] = new int[3];
            n[2] = new int[2];
            // n[1] = new int[] { 1, 2, 3 };
            // Console.WriteLine("enter the rollno");
            for (i = 0; i < 4; i++)
            {

                n[0][i] = Convert.ToInt32(Console.ReadLine());


            }
            for (i = 0; i < 3; i++)
            {

                n[1][i] = Convert.ToInt32(Console.ReadLine());


            }
            for (i = 0; i < 2; i++)
            {

                n[2][i] = Convert.ToInt32(Console.ReadLine());


            }


            //   for (i = 0; i < 3; i++)
            // {
            //   n[i][j] = Convert.ToInt32(Console.ReadLine());
            //}

            for (i = 0; i <4; i++)
            
                              {
                    Console.Write(n[0][i] + " ");
                }
            Console.WriteLine();
           for (i = 0; i < 3; i++)
            
                    {
                        Console.Write(n[1][i] + " ");
                    }

                

            }
    }
}

输入锯齿状数组的值

2 个答案: