从collectionType [Symfony]

Question

我正在尝试使用Symfony为我的应用程序创建一个测验。 此时我有3个班级，Qcm，QcmQuestion和QcmAnswer。 我有多个问题，其中包含多个答案，我想将答案显示为单选按钮。

我只是将它们显示为输入。如何将它们显示为单选按钮？

BaseController.php

 $em = $this->getDoctrine()->getManager()>getRepository('QcmBundle:QcmQuestion');
    $qcmQuestions = $em->findBy(array('qcm' => $id));
            $formBuilderQuestionnaire = $this->createFormBuilder();
            $i = 0;
            foreach ($qcmQuestions as $qcmQuestion) {
                $formBuilder = $this->get('form.factory')->createNamedBuilder($i, FormType::class, $qcmQuestion);
                $formBuilder
                    ->add('question')
                    ->add('qcmAnswers', CollectionType::class, [
                        'entry_type' => QcmAnswerType::class
                    ])
   ;
                $formBuilderQuestionnaire->add($formBuilder);
                $i++;
            }
            $form = $formBuilderQuestionnaire->getForm();
            $form->add('save', SubmitType::class, array('label' => 'Envoyer',
                "attr" => array("class" => "btn btn-primary")));
            return $this->render('QcmBundle:qcm:qcmQuestions.html.twig', ["qcmQuestions" => $qcmQuestions, "form" => $form->createView()]);

QcmAnswerType

class QcmAnswerType extends AbstractType
{
    public function buildForm(FormBuilderInterface $builder, array $options)
    {
        $builder->add('response');
    }

    public function configureOptions(OptionsResolver $resolver)
    {
        $resolver->setDefaults(array(
            'data_class' => 'QcmBundle\Entity\QcmAnswer'
        ));
    }

    public function getBlockPrefix()
    {
        return 'qcmbundle_qcmanswer';
    }

Answer 1

您不希望QcmAnswerType + EntityType，但只希望multiple: false选项expanded: true和 ->add('qcmAnswers', CollectionType::class, [ 'entry_type' => QcmAnswerType::class ]) 。

所以而不是

   ->add('qcmAnswers', EntityType::class, [
        'multiple' => false,
        'expanded' => true,
    ])

尝试使用类似的东西：

String h = " { "
                + " \"script\": { \n"
                + " \"inline\": \"ctx._source.order=params.prasad\", \n "
                + "\"params\": { \"prasad\":["+column+"] \n"
                + " } , \n"
                + "\"lang\": \"painless\" \n"
                + "},\n"
                + "\"query\": { \n"
                + "\"term\": { \n"
                + "\"orgid\": "+orgId+" \n"
                + "} \n"
                + "}";

有关EnttiyType的更多信息，请参阅Symfony Docs。

Answer 2

我设法解决了我的问题，我在EntityType中使用了查询。

Entities passed to the choice field must be managed. Maybe persist them in the entity manager?"

我遇到了这个错误，因为我需要将createNamedBuilder这样的问题传递给 $formBuilder = $this->get('form.factory')->createNamedBuilder($i, FormType::class, $qcmQuestions); ：

 $em = $this->getDoctrine()->getManager()->getRepository('QcmBundle:QcmQuestion');
        $qcmQuestions = $em->findBy(array('qcm' => $id));
        $formBuilderQuestionnaire = $this->createFormBuilder();
        $i = 0;
        foreach ($qcmQuestions as $qcmQuestion) {
            /* @var $qcmQuestion QcmQuestion */
            $formBuilder = $this->get('form.factory')->createNamedBuilder($i, FormType::class, $qcmQuestions);
            $formBuilder
                ->add('qcmAnswers', EntityType::class, [
                    'class' => 'QcmBundle\Entity\QcmAnswer',
                    'expanded' => true,
                    'label' => $qcmQuestion->getQuestion(),
                    'query_builder' => function (EntityRepository $er) use ($qcmQuestion) {
                        return $er->createQueryBuilder('qcmAnswer')
                            ->join('qcmAnswer.qcmQuestion', 'qcmQuestion')
                            ->where('qcmAnswer.qcmQuestion = :qcmQuestionId')
                            ->setParameter('qcmQuestionId', $qcmQuestion->getId());
                    },
                ]);
            $formBuilderQuestionnaire->add($formBuilder);
            $i++;
        }
        $form = $formBuilderQuestionnaire->getForm();

最终结果：

{{1}}