如何复制一些buildscript类路径JAR但在Gradle中排除其他JAR？

Question

我有一个引用许多JAR的buildscript块：

buildscript {
    dependencies { classpath "com.github.kulya:jmeter-gradle-plugin:1.3.4-2.13" }
    dependencies { classpath "com.eriwen:gradle-css-plugin:2.14.0" }
    dependencies { classpath "com.eriwen:gradle-js-plugin:2.14.1" }
    dependencies { classpath "com.google.javascript:closure-compiler:v20160208" }
    dependencies { classpath "org.akhikhl.gretty:gretty:+" }
}

task copyWarGradlePlugins(type: Copy) {
    destinationDir = file(project.buildDir.name + '/warGradlePlugins')

    from (buildscript.configurations.classpath)
}

我想复制（到我的WAR文件）一些引用的JAR（例如gradle-css-plugin，gradle-js-plugin，closure-compiler的依赖项）但不是其他的（例如gretty，jmeter-gradle-plugin） ）。

如何排除例如jmeter-gradle-plugin及其所有依赖项？

更新：
有超过150个JAR。按文件名排除它们是不实际/可维护的。

Answer 1

buildscript {
    dependencies { classpath "com.github.kulya:jmeter-gradle-plugin:1.3.4-2.13" }
    dependencies { classpath "com.eriwen:gradle-css-plugin:2.14.0" }
    dependencies { classpath "com.eriwen:gradle-js-plugin:2.14.1" }
    dependencies { classpath "com.google.javascript:closure-compiler:v20160208" }
    dependencies { classpath "org.akhikhl.gretty:gretty:+" }
}

task copyWarGradlePlugins(type: Copy) { copy ->
    destinationDir = file(project.buildDir.name + '/warGradlePlugins')

    copy.from(buildscript.configurations.classpath) { copySpec ->
        // exclusions are based on the file name as here you will be handed
        // DefaultFileVisitDetails type
        copySpec.exclude { it.name.startsWith 'gretty' }
        copySpec.exclude { it.name.startsWith 'closure-compiler' }
    }
}