Question

您好，目前我正在努力开发一个项目，但我遇到了障碍，我已经盯着这段代码几个小时了，无法弄清楚发生了什么

我的主要问题是找到用户输入的数组的最小值...我能够获得最大值和输出，但由于某种原因，我无法得到最小值输出正确的结果。我一直都是0.0 ....

#include <stdio.h>
#include <stdlib.h>
#define SIZE 5
double getValidRainfall() {
double result;

printf("\nEnter a rainfall amount: ");
scanf("%lf", &result);

while (result < 0.0) {
    printf("%.2lf is not a valid rainfall amount.", result);
    printf("\nEnter another rainfall amount: ");
    scanf("%lf", &result);
}
return result;
}
double calculateTotal(double rainfall[], int size) {
double result = 0.0;
int i;
for (i = 0; i < SIZE; i++) {
    result += rainfall[i];
}
return result;
}

double findLargest(double rainfall[], int size) {
double result = 0.0;
int i;
for (i = 0; i < size; i++) {
    if (rainfall[i] > result)
        result = rainfall[i];
}
return result;
}

double findSmallest(double rainfall[], int size) {
double result = 0.0;
int i;

for (i = 0; i < size; i++) {
    if (rainfall[i] < result) 
        result = rainfall[i];
}
return result;
}

main() {
double rainfall[SIZE], totalRainfall, averageRainfall;
double largestRainfall, smallestRainfall;
int i;

for(i = 0; i < SIZE; i++)
    rainfall[i] = getValidRainfall();

totalRainfall = calculateTotal( rainfall, SIZE );
averageRainfall = totalRainfall / SIZE;
largestRainfall = findLargest(rainfall, SIZE);
smallestRainfall = findSmallest(rainfall, SIZE);


// outputs
printf("\nThank you.\n");
printf("The total rainfall for these 5 days is: %.2lf\n", totalRainfall);
printf("The average rainfall is %.2lf\n", averageRainfall);
printf("The largest daily rainfall is %.1lf\n", largestRainfall);
printf("The smallest daily rainfall is %.1lf\n", smallestRainfall);

system("pause");
}

Answer 1

在下面的函数中，将result分配给可能的最大值或者从数组本身分配一个，否则，它将给出错误的结果，因为0.0将始终小于数组中的任何值（考虑到降雨量a + ve数量）＆amp;这种情况总是错误的。

double findSmallest(double rainfall[], int size) {
    double result = DBL_MAX; // or double result = rainfall[0], if size >= 1;
    int i;

    for (i = 0; i < size; i++) {
        if (rainfall[i] < result) 
            result = rainfall[i];
    }
    return result;
}

Answer 2

显然，所有降雨条目都需要0.0将result初始化为一个极高值，而不是零。

Answer 3

您需要将结果变量初始化为数组中的第一个元素或高于所有值的值（第一个方法更有效）。由于您将其初始化为0.0，除非值为负，否则将保持为0.0。因此我建议：

double result = rainfall[0];

使用函数在数组中查找最小值？

3 个答案: