Question

新手到xslt。我有一个无法更改的xml文件，如下所示。 id属性将存在于所有元素中，但其他变量可能存在也可能不存在。任何帮助在xslt中表示这一点非常感谢！谢谢！

<A>
   <B>
      <att id="1" var1="ABC" var2="DEF" />
      <att id="2" var2="FGD" />
      <att id="3" var1="ABC" var3="KQR" />
   </B>
   <C>
      <att id="5" var1="ABC" var2="DEF" />
      <att id="8" var3="FGD" />
      <att id="9" var1="ABC" var4="KQR" />
   </C>
   <D>
      <att id="11" var1="ABC" var2="DEF" />
      <att id="13" var5="FGD" var6="TRE" />
      <att id="14" var1="ABC" var3="KQR" />
   </D>
</A>

我想创建如下所示的HTML表格：

A (Header)
B (Sub-Header)
--------------------------
|ID | Var1 | Var2 | Var3 |
|1  | ABC  | DEF  |      |
|2  |      | FGD  |      |
|3  | ABC  |      | KQR  |
--------------------------
C (Sub-Header)
---------------------------------
|ID | Var1 | Var2 | Var3 | Var4 | 
|5  | ABC  | DEF  |      |
|8  |      |      | FGD  |      |      
|9  | ABC  |      |      | KQR  |
---------------------------------
D (Sub-Header)
----------------------------------------
|ID | Var1 | Var2 | Var3 | Var5 | Var6 | 
|11 | ABC  | DEF  |      |      |      |
|13 |      |      |      | FGD  | TRE  |   
|14 | ABC  |      | KQR  |      |      |
----------------------------------------

Answer 1

哇哇哇哇哇哇哇哇哇哇哇哇哇哇哇哇哇哇哇哇哇哇哇哇哇哇哇哇哇哇哇哇哇哇哇

这样的事似乎有用......

<?xml version="1.0"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="html"/>

<xsl:key name="kAttsByGrandparent" match="@*[not(local-name() = 'id')]" use="generate-id(ancestor::*[2])"/>
<xsl:key name="kDistinctAttsByGrandparent" match="@*[not(local-name() = 'id')]" use="concat(generate-id(ancestor::*[2]), '||', local-name())"/>

<xsl:key name="distinct" match="att" use="."/>
<xsl:template match="/">
    <html>
        <body>
            <xsl:apply-templates/>
        </body>
    </html>
</xsl:template>

<xsl:template match="*">
    <h1>
        <xsl:value-of select="local-name()"/>
    </h1>
    <xsl:apply-templates/>
</xsl:template>

<xsl:template match="*[att]">
    <h1>
        <xsl:value-of select="local-name()"/>
    </h1>
    <xsl:variable name="vGrandparentId" select="generate-id()"/>
    <xsl:variable name="vDistinctAttNames" select="key('kAttsByGrandparent', $vGrandparentId)[generate-id() = generate-id(key('kDistinctAttsByGrandparent', concat($vGrandparentId, '||', local-name()))[1])]"/>
    <table border="1">
        <!-- header row -->
        <tr>
            <th>
                <xsl:text>ID</xsl:text>
            </th>
            <xsl:for-each select="$vDistinctAttNames">
                <xsl:sort select="local-name()"/>
                <th>
                    <xsl:value-of select="local-name()"/>
                </th>
            </xsl:for-each>
        </tr>
        <xsl:apply-templates select="att">
            <xsl:with-param name="pDistinctAttNames" select="$vDistinctAttNames"/>
        </xsl:apply-templates>
    </table>
    <xsl:apply-templates select="*[not(local-name() = 'att')]"/>
</xsl:template>

<xsl:template match="att">
    <xsl:param name="pDistinctAttNames"/>
    <tr>
        <td>
            <xsl:value-of select="@id"/>
        </td>
        <xsl:variable name="vThisElement" select="."/>
        <xsl:for-each select="$pDistinctAttNames">
            <xsl:sort select="local-name()"/>
            <td>
                <xsl:variable name="vAttName" select="local-name()"/>
                <xsl:value-of select="$vThisElement/@*[local-name() = $vAttName]"/>
            </td>
        </xsl:for-each>
    </tr>
</xsl:template>
</xsl:stylesheet>

Answer 2

我确实在线https://www.w3schools.com/xml/tryxslt.asp和cli上的xsltproc

XSLT-文件

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<html>
<body>
  <h1>A</h1>
  <h2>B</h2>
  <table border="1">
<tr><th>id</th><th>var1</th><th>var2</th><th>var3</th></tr>
    <xsl:for-each select="/A/B/att">
    <tr>
      <td><xsl:value-of select="@id"/></td>
      <td><xsl:value-of select="@var1"/></td>
      <td><xsl:value-of select="@var2"/></td>
      <td><xsl:value-of select="@var3"/></td>
    </tr>
    </xsl:for-each>
  </table>
  <h2>C</h2>
  <table border="1">
<tr><th>id</th><th>var1</th><th>var2</th><th>var3</th><th>var4</th></tr>
    <xsl:for-each select="/A/C/att">
    <tr>
      <td><xsl:value-of select="@id"/></td>
      <td><xsl:value-of select="@var1"/></td>
      <td><xsl:value-of select="@var2"/></td>
      <td><xsl:value-of select="@var3"/></td>
      <td><xsl:value-of select="@var4"/></td>
    </tr>
    </xsl:for-each>
  </table>
  <h2>D</h2>
  <table border="1">
<tr><th>id</th><th>var1</th><th>var2</th><th>var3</th><th>var5</th><th>var6</th></tr>
    <xsl:for-each select="/A/D/att">
    <tr>
      <td><xsl:value-of select="@id"/></td>
      <td><xsl:value-of select="@var1"/></td>
      <td><xsl:value-of select="@var2"/></td>
      <td><xsl:value-of select="@var3"/></td>
      <td><xsl:value-of select="@var5"/></td>
      <td><xsl:value-of select="@var6"/></td>
    </tr>
    </xsl:for-each>
  </table>
</body>
</html>
</xsl:template>
</xsl:stylesheet>

你可以打电话给他，例如xsltproc template.xslt data.xml。

xsl帮助html表

2 个答案: