我在我的网站上添加了一个类似按钮，点击它时会突出显示，但不增加喜欢的数量或显示管理中的计数。我不明白我做错了什么。请帮我解决这个问题。我的代码如下。
class Post(models.Model):
post = models.TextField()
user = models.ForeignKey(User)
created = models.DateTimeField(auto_now_add=True)
updated = models.DateTimeField(auto_now=True)
likes = models.IntegerField(default=0)
def __str__(self):
return self.post
@login_required
def about(request,pk):
context = {}
template = 'about.html'
return render(request, template, context)
post = get_object_or_404(Post, pk=pk)
Post.objects.get(pk=pk)
post_id = post.pk
liked = False
if request.session.get('has_liked_' + str(post_id), liked):
liked = True
print("liked {}_{}".format(liked, post_id))
context = {'post': post, 'liked': liked}
return render(request, 'imagec/about.html', {'post': post})
@login_required()
def like_post(request):
liked = False
if request.method == 'GET':
post_id = request.GET['post_id']
post = Post.objects.get(id=int(post_id))
if request.session.get('has_liked_'+post_id, liked):
print("unlike")
if post.likes > 0:
likes = post.likes - 1
try:
del request.session['has_liked_'+post_id]
except KeyError:
print("keyerror")
else:
print("like")
request.session['has_liked_'+post_id] = True
likes = post.likes + 1
post.likes = likes
post.save()
return HttpResponse(likes, liked)
url(r'like_post/$', imagec_views.like_post, name='like_post'),
<p>
<strong id="like_count">{{ post.likes }}</strong> people like this category
{% if user.is_authenticated %}
<input type="button" onclick="jQuery(this).toggleClass('active')" data-post_id="{{post.id}}" id="likes" value ='Like'>
{% endif %}
</p>
<script type="text/javascript" src="{% static 'js/blog-ajax.js' %}"></script>
<script type="text/javascript" src="{% static 'js/jquery-3.js' %}"></script>
<script src="{% static 'js/jquery-3.js' %}"></script>
<script src="{% static 'js/blog-ajax.js' %}"></script>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<script src = {% static "js/ajax-blog.js" %}> </script>
<script src = {% static "js/jquery-3.js" %}> </script>
$('#likes').click(function(){
var postid;
postid= $(this).attr("data-post_id");
$.get('/imagec/like_post/', {post_id: postid}, function(data){
$('#like_count').html(data);
});
});
谢谢
答案 0 :(得分：1)
您可以使用console.log侧的JS和print侧的Python进行调试。
<强> Ajax的blog.js
$('#likes').click(function(){
var postid;
postid= $(this).attr("data-post_id");
console.log("Post id to be send " + postid);
$.get('/imagec/like_post/', {post_id: postid}, function(data){
console.log("data received: "+data);
$('#like_count').html(data);
});
});
<强> views.py
@login_required
def about(request,pk):
context = {}
template = 'about.html'
return render(request, template, context)
post = get_object_or_404(Post, pk=pk)
Post.objects.get(pk=pk)
post_id = post.pk
liked = False
if request.session.get('has_liked_' + str(post_id), liked):
liked = True
print("liked {}_{}".format(liked, post_id))
context = {'post': post, 'liked': liked}
return render(request, 'imagec/about.html', {'post': post})
@login_required()
def like_post(request):
liked = False
if request.method == 'GET':
post_id = request.GET['post_id']
post = Post.objects.get(id=int(post_id))
if request.session.get('has_liked_'+post_id, liked):
print("unlike")
if post.likes > 0:
likes = post.likes - 1
try:
del request.session['has_liked_'+post_id]
except KeyError:
print("keyerror")
else:
print("like")
request.session['has_liked_'+post_id] = True
likes = post.likes + 1
post.likes = likes
print("updated liked ", post.likes)
post.save()
return HttpResponse(likes, liked)
检查控制台打印。
除此之外，我最终有两个主要建议，