Question

我的用户节点中有年龄字段我需要按照以下群组按年龄分组。

'0-9', 
'10-19', 
'20-29', 
'30-39',
'40-49', 
'50-59', 
'60-69', 
'70-79', 
'80-89',
'90-99', 
'100 +'

我使用了以下查询

MATCH (n:users)   RETURN count(n.age<25) as group1,count(n.age>25 AND n.age<30) as group2

但是获取错误的用户数。任何人都有想法请在这里分享。

Answer 1

问题是count函数计算变量的出现次数，无论其值如何：

UNWIND [true, false, true, true] as test
RETURN count(test = true)

所以，你可以尝试这样的事情：

UNWIND [15, 15, 26, 29, 17, 18, 7, 14, 25, 14] as age
RETURN sum(CASE WHEN age<=25 and age>10 THEN 1 ELSE 0 END) as group1,
       sum(CASE WHEN age<=30 and age>25 THEN 1 ELSE 0 END) as group2

<强> UPD ：

在我看来，这是一种更简单的计算分布的方法：

UNWIND [15, 15, 26, 29, 17, 18, 0, 14, 25, 14] as age
WITH age,
     REDUCE(acc='', 
              r in [ [0,10,'group1'], [10,20,'group2'], [20,30,'group3'] ] | 
              acc + CASE WHEN age>=r[0] AND age<r[1] THEN r[2] ELSE '' END
     ) as group
     WHERE size(group)>0
RETURN group, count(age)

Neo4J Group By Age Cypher Query

1 个答案: