我需要在UI上显示对实体进行修改的历史记录。像这样的东西 -
|-------------------------------------------------------------------------------------------------------------------------------------|
|Entity name | Entity ID | Action by | Action on | Action Type | Old value | New value |
|-------------|-------------|-------------|----------------------|---------------|--------------------------|-------------------------|
|Person | 1 | John Doe | 2017-04-12 12:00:00 | Add | | name: Lily, Role: Admin |
|Person | 1 | John Doe | 2017-04-15 12:00:00 | Update |name: Lily | name: Lily Smith |
|Subject | 5 | Mary | 2017-04-17 12:00:00 | Update |name: Maths | name: Mathematics |
|Subject | 6 | Mary | 2017-04-17 12:00:00 | Delete |name: Science, credits: 5 | |
|-------------------------------------------------------------------------------------------------------------------------------------|
我使用Hibernate envers来存储我需要的所有数据。但是我在阅读所有数据时遇到了问题，以显示我上面需要的内容。我在互联网上搜索了很多博客，问题文章，文档，javadocs，但没有一个显示如何做到这一点。所有这些都显示了如何根据修订版或返回修订版检索实体。除了返回的实体之外，这些实体都没有以下信息 -
请注意，我希望尽可能少的查询来加速历史记录API响应。
我正在使用hibernate和envers版本：＆＃39; 5.2.9.Final＆＃39;
高度赞赏的任何帮助。
谢谢！
这是代码 -
每个实体类上方的注释 -
@Audited(withModifiedFlag = true)
自定义修订监听器 -
public class CustomRevisionListener implements RevisionListener {
private static final Logger logger =
LogManager.getLogger(CustomRevisionListener.class);
public void newRevision(Object revisionEntity) {
logger.info("newRevision, starts revisionEntity="+revisionEntity);
CustomRevisionEntity revision = (CustomRevisionEntity) revisionEntity;
String name = "unknown";
try{
//user custom userdetails.User to store id and name both?
//or just store id in string format here?
org.springframework.security.core.userdetails.User springUser =
(org.springframework.security.core.userdetails.User) SecurityContextHolder
.getContext().getAuthentication().getPrincipal();
name = springUser.getUsername(); //get logged in username
}catch(Exception e){
logger.error("error getting username", e);
}
logger.info("newRevision, name="+name);
User user = new User();
user.setName(name);
revision.setUser(user); //for testing
logger.info("newRevision, setting userId="+user.getId());
}
}
自定义修订实体 -
@Entity
@Table(name="REVISIONS")
@RevisionEntity(CustomRevisionListener.class)
public class CustomRevisionEntity extends DefaultRevisionEntity {
private static final long serialVersionUID = -6113123831136684807L;
@ManyToOne
@JoinColumn(name="USER_ID")
private User user;
public User getUser() {
return user;
}
public void setUser(User user) {
this.user = user;
}
}
envers config -
org.hibernate.envers.track_entities_changed_in_revision=true
org.hibernate.envers.global_with_modified_flag=true
org.hibernate.envers.store_data_at_delete=true
org.hibernate.envers.audit_strategy=org.hibernate.envers.strategy.ValidityAuditStrategy
org.hibernate.envers.audit_strategy_validity_store_revend_timestamp=true
阅读审核 -
public List getAllAudits() {
logger.debug("getAllAudits starts");
//HERE IS WHERE I NEED HELP.
//below code is just for trials. I need something which will read all audits and relevant info I described above
ArrayList list = (ArrayList) AuditReaderFactory.get(entityManager)
.createQuery()
.forRevisionsOfEntity(Organization.class, true, true)
// .add(AuditEntity.id().eq(bitacoraControlId))
.addOrder(AuditEntity.revisionNumber().asc())
.getResultList();
for(int i=0; i revisions = reader.getRevisions(Organization.class, 2);
for(Number revNum:revisions){
Organization article =reader.find(Organization.class, 2, revNum);
System.out.println("Revision No: " + revNum);
System.out.println("Title: " + article.getId());
System.out.println("Content: " + article.getName());
}
logger.debug("getAllAudits list size="+list.size());
return list;
}