在Emacs中将特定列除以100

Question

我试图在emacs中将第二列的所有值（Tide（cm））除以100。有谁可以帮助我如何从linux命令提示符那样做？

Here is the screenshot of the file

感谢。

Answer 1

如果你想使用shell，请使用perl而不是emacs：

给出这个文件：

  

cat new.txt   一些标题
  不关心潮流（护理）dc dc dc
   0.00 17.873 5 bla kuku
   1.00 36.53 lkfj kuku 42

@Entity @Table(name="svc_category") @JsonIdentityInfo(generator=ObjectIdGenerators.PropertyGenerator.class, property="id") public class ServiceCategoryDomain extends BaseDomain{ private static final long serialVersionUID = -5873300401604877065L; @Column(name="svc_cde") @NotNull private Integer svcCode; @Column(name="svc_name") @NotNull private String svcName; @JsonBackReference("parent") @ManyToOne private ServiceCategoryDomain parent; @JsonManagedReference("children") @OneToMany (cascade = {CascadeType.ALL},mappedBy="parent") private Collection<ServiceCategoryDomain> children=new ArrayList<>(); .................. }

  

一些标题
  不关心潮流（护理）dc dc dc
   0.00 0.17873 5 bla kuku
   1.00 0.3653 lkfj kuku 42

Answer 2

如何使用emacs组织模式将第二列除以10

1) mark region

Col1 Col2 Col3
1 2 3
4 5 6
7 8 9
10 11 12

2) M-x, then org-table-create-or-convert-from-region
3) insert a horizontal line to seperate the column headers from the
   data by putting a: ‘|-‘ (without the quotes) one the line and hit
   the tab button

should look like:

| Col1 | Col2 | Col3 |
|------+------+------|
|    1 |    2 |    3 |
|    4 |    5 |    6 |
|    7 |    8 |    9 |
|   10 |   11 |   12 |

4) org-table-eval-formula, but for whole column:
‘C-5 C-c =’
5) then type the formula as $2/10.0 so that the prompt looks like:
Column formula $2=$2/10.0

should look like:

| Col1 | Col2 | Col3 |
|------+------+------|
|    1 |  0.2 |    3 |
|    4 |  0.5 |    6 |
|    7 |  0.8 |    9 |
|   10 |  1.1 |   12 |
#+TBLFM: $2=$2/10.0

there are a bunch of export options