Question

print_r（$ a）的结果是

views_handle_field_node Object

    (

    [view]=>view Object

   (
 [db_table] => views_view
 [base_table] => node
 [args] => Array
    (
        [0] => My entry 1
    )

[use_ajax] =>
[result] => Array
    (
        [0] => stdClass Object
            (
                [nid] => 5
                [node_title] => Title of a test entry
                [node_revisions_body] =>
                [node_revisions_format] => 1
                [node_vid] => 5
                [term_data_name] => My first test term name
                [term_data_vid] => 1
                [term_data_tid] => 1
                [vocabulary_name] => Vocabulary 1
                [node_revisions_vid] => 5
            )

        [1]=> stdClass Object
              (
                 [nid] => 8
                [node_title] => Title of a test entry
                [node_revisions_body] =>
                [node_revisions_format] => 1
                [node_vid] => 5
                [term_data_name] => My first test term name
                [term_data_vid] => 1
                [term_data_tid] => 1
                [vocabulary_name] => Vocabulary 1
                [node_revisions_vid] => 5
        ..
        [2]..
         ..

如何使用一个变量的名称来输出[nid] =＆gt; 5和[nid] =＆gt; 8 .....并且所有nid.i都使用它，但是无法工作。

$ views_handle_field_node-＆GT; $视图 - ＆GT; $导致[] - ＆GT; NID

Answer 1

变量名称为$a而非`$ views_handle_field_node'，请尝试：

$first = $a->view->result[0]->nid;

//access all of the results?
foreach ($a->view->result as $obj) {
    //do something with $obj->nid;
}

如果这没有用，那么告诉我们上下文是什么？您是将此代码放在模块挂钩还是模板文件中？我那种情况下是什么类型的视图设置。告诉我们“风格”和“行式”。

Answer 2

$first = $views_handle_field_node->view->result[0]->nid;

//access all of the results?
foreach ($views_handle_field_node->view->result as $obj) {
    //do something with $obj->nid;
}

drupal views ---如何输出它

2 个答案: