Hive查询分别从String中提取日期和小时

时间:2017-04-23 20:49:51

标签: hadoop hive hiveql

我需要从配置单元中的字符串列中提取日期和小时。

表: enter image description here

select TO_DATE(from_unixtime(UNIX_TIMESTAMP(dates,'dd/MM/yyyy'))) from dates;

output:

0016-01-01
0016-01-01

select TO_DATE(from_unixtime(UNIX_TIMESTAMP(dates,'hh'))) from dates;

output:

1970-01-01
1970-01-01

请告知如何从表格栏中单独和小时分别列出日期。

1 个答案:

答案 0 :(得分:3)

我已将数据样本更改为更合理的

with dates as (select explode(array('1/11/16 3:29','12/7/16 17:19')) as dates)

select  from_unixtime(unix_timestamp(dates,'dd/MM/yy HH:mm'),'yyyy-MM-dd')  as the_date
       ,from_unixtime(unix_timestamp(dates,'dd/MM/yy HH:mm'),'H')           as H
       ,from_unixtime(unix_timestamp(dates,'dd/MM/yy HH:mm'),'HH')          as HH

from    dates
+------------+----+----+
|  the_date  | h  | hh |
+------------+----+----+
| 2016-11-01 |  3 | 03 |
| 2016-07-12 | 17 | 17 |
+------------+----+----+