如何计算嵌套SQL语句的平均值？

Question

我有这个疯狂的嵌套sql语句，它返回如下内容：

但是，我想要的是在图像中使用此数据返回2列。 col_1 ：SUM(avgWithCriteria)/43和 col_2 ：SUM(avgWithoutCriteria)/43。如何在下面添加我的查询来完成此操作？

    SELECT
    ( ( avgWithCriteria - totalAverage ) / ( ( avgWithCriteria + totalAverage ) / 2 ) ) * 100 as percentDifference,
    a.*
FROM 
    (SELECT
        AVG( CASE WHEN 'f' not in ( has_free_parking ) THEN price ELSE null END) as avgWithCriteria,
        AVG( CASE WHEN 'f'        in ( has_free_parking ) THEN price ELSE null END) as avgWithoutCriteria,
        AVG( price ) as totalAverage,
        neighbourhood_cleansed
    FROM listings 
   WHERE city_name="berlin"
   AND price <= 1000000
   AND price >= -1
   AND reviews_per_month <= 1000000
   AND reviews_per_month >= -1
   AND est_monthly_income <= 1000000
   AND est_monthly_income >= -1
   GROUP BY neighbourhood_cleansed ) a;

Answer 1

试试这个： -

SELECT percentDifference,avgWithCriteria,avgWithoutCriteria,totalAverage,neighbourhood_cleansed,
(col1_1/43) as col1,(col2_2/43) as col2
from
(
SELECT a.*,SUM(avgWithCriteria) as col1_1,SUM(avgWithoutCriteria) as col2_2
FROM
  (
SELECT
    ( ( avgWithCriteria - totalAverage ) / ( ( avgWithCriteria + totalAverage ) / 2 ) ) * 100 as percentDifference,
    a.*
FROM 
    (SELECT
        AVG( CASE WHEN 'f' not in ( has_free_parking ) THEN price ELSE null END) as avgWithCriteria,
        AVG( CASE WHEN 'f'        in ( has_free_parking ) THEN price ELSE null END) as avgWithoutCriteria,
        AVG( price ) as totalAverage,
        neighbourhood_cleansed
    FROM listings 
   WHERE city_name="berlin"
   AND price <= 1000000
   AND price >= -1
   AND reviews_per_month <= 1000000
   AND reviews_per_month >= -1
   AND est_monthly_income <= 1000000
   AND est_monthly_income >= -1
   GROUP BY neighbourhood_cleansed ) a
  ) a
GROUP BY percentDifference,avgWithCriteria,avgWithoutCriteria,totalAverage,neighbourhood_cleansed
) a;

Answer 2

SELECT
    ( ( avgWithCriteria - totalAverage ) / ( ( avgWithCriteria + totalAverage ) / 2 ) ) * 100 as percentDifference,
    SUM(avgWithCriteria)/43 AS col_1,
    SUM(avgWithoutCriteria)/43 AS col_2,
    a.*
FROM 
    (SELECT
        AVG( CASE WHEN 'f' not in ( has_free_parking ) THEN price ELSE null END) as avgWithCriteria,
        AVG( CASE WHEN 'f'        in ( has_free_parking ) THEN price ELSE null END) as avgWithoutCriteria,
        AVG( price ) as totalAverage,
        neighbourhood_cleansed
    FROM listings 
WHERE city_name="berlin"
AND price <= 1000000
AND price >= -1
AND reviews_per_month <= 1000000
AND reviews_per_month >= -1
AND est_monthly_income <= 1000000
AND est_monthly_income >= -1
GROUP BY neighbourhood_cleansed ) a;