与flatpages reverse()
一起使用时,get_abolute_url()
会返回不同的输出:
>>> about = FlatPage.objects.get(id=2)
>>>
>>> about
<FlatPage: /about-us/ -- About us page>
>>>
>>> about.url
>>> '/about-us/'
>>>
>>> about.get_absolute_url()
'/about-us/'
>>>
>>>
>>> reverse('django.contrib.flatpages.views.flatpage', args=[about.url])
'/%2Fabout-us/' ## from where %2F comes from ?
>>>
以下是网站范围urls.py
:
from django.conf.urls import url, include
from django.contrib import admin
from django.contrib .flatpages import urls as flatpage_urls
# from . import blog
urlpatterns = [
url(r'^admin/', admin.site.urls),
url(r'', include(flatpage_urls)),
]
虽然,我可以访问http://127.0.0.1:8000/about-us/
处的某个页面。 %2F
来自哪里?
我原以为两种方法都应该返回相同的输出。这是怎么回事?
更新
以下是flatpages/urls.py
from django.conf.urls import url
from django.contrib.flatpages import views
urlpatterns = [
url(r'^(?P<url>.*)$', views.flatpage, name='django.contrib.flatpages.views.flatpage'),
]
更新2:
将urls.py更新为:
urlpatterns = [
url(r'^admin/', include(admin.site.urls)),
# url(r'', include(flatpage_urls)),
]
urlpatterns += [
url(r'^(?P<url>.*/)$', views.flatpage),
]
答案 0 :(得分:0)
在我看来,你试图在另一个URL中插入一个URL,这看起来很奇怪。
从你的代码:
reverse('django.contrib.flatpages.views.flatpage', args=[about.url])
您还澄清了about.url
包含/about-us/
。此字符串将被引用并插入URL:
http://hostname.example/<here>/
或者:
http://hostname.example/%2Fabout-us%2F/
我不明白为什么你没有看到最后一个%2F。
答案 1 :(得分:0)
django.contrib.flatpages
显然与reverse()
与args或kwargs不兼容。预期用途是使用其自定义标记:
{% load flatpages %}
{% get_flatpages as flatpages %}
<ul>
{% for page in flatpages %}
<li><a href="{{ page.url }}">{{ page.title }}</a></li>
{% endfor %}
</ul>
来源Flatpages > Getting a list of FlatPage objects in your templates
FlatPage.get_absolute_url()
仅返回self.url
字段中的任何内容,在您的示例中,该字段是由斜杠包围的字符串,即&#39; / about-us /&#39;。
def get_absolute_url(self):
# Handle script prefix manually because we bypass reverse()
return iri_to_uri(get_script_prefix().rstrip('/') + self.url)
另一方面,reverse()
调用_reverse_with_prefix()
,其前缀为网址斜杠/
,结果为//about-us/
。然后,它错误地确定双斜杠表示尝试的模式重写,因此它用URL ASCII代码%2f
替换第二个斜杠以中和它。
不幸的是,FlatPage.url
的表单验证程序要求违反前导/
:
def clean_url(self):
url = self.cleaned_data['url']
if not url.startswith('/'):
raise forms.ValidationError(
ugettext("URL is missing a leading slash."),
...
您可以使用不带斜杠的前缀来解决它,例如:
url(r'^pages', include(django.contrib.flatpages.urls))
但这也会匹配pagesabout-us/
。如果您使用r'^'
完全删除前缀,则_reverse_with_prefix()
会在/
前加上,以避免相对链接。
您可以像https://docs.djangoproject.com/en/1.11/ref/contrib/flatpages/#using-the-urlconf中的第3个示例那样对网址进行硬编码,但这会破坏在flatpages表中管理网址的目的。
from django.contrib.flatpages import views
urlpatterns += [
url(r'^about-us/$', views.flatpage, {'url': '/about-us/'}, name='about'),
url(r'^license/$', views.flatpage, {'url': '/license/'}, name='license'),
]