Question

我目前在创建json响应时遇到问题，因为我没有那么多使用PHP，但任何人都可以帮我创建json，如下所示：

{
  "set_attributes": 
    {
      "apikey": "some value",
    },
  "block_names": ["getdata"],
  "type": "show_block",
  "title": "go"
}

这是我的代码：

    $response = array();
    $response['block_names'] = array();
    $response['block_names'] = "getdata";
    $response['type'] = "show_block";
    $response['title'] = "go";

    if ($db->studentLogin($username, $password)) {
        $student = $db->getStudent($username);
        $temp = array();
        $temp['apikey'] = $student['api_key'];
        $response['set_attributes'] = $temp['apikey'];
    } else {
        $temp = array();
        $response['messages'] = array();
        $temp['text'] = "Invalid username or password";
        array_push($response['messages'],$temp);
    }
    echoResponse(200, $response);

它显示如下：

{
  "block_names": "getdata",
  "type": "show_block",
  "title": "go",
  "set_attributes": "f74911b29778adea86aa24d5ce85ff58"
}

但我想添加apikey =＆＃34; f74911b29778adea86aa24d5ce85ff58＆＃34;在set_attributes和[]之外的block_names就像obove一样。我怎么能这样做？

Answer 1

试试这个：

$response['block_names'] = array("getdata");
...
$response['set_attributes'] = new \stdClass();
$response['set_attributes']->apikey = 'some_api_key';

https://3v4l.org/GDMKT#output

如何在php中添加对象内的对象？

1 个答案: