我想从另一个表单打开一个表格按钮。 我怎么能这样做？
private void button1_Click(object sender, EventArgs e)
{
Form Grondstoffen = new Form();
Grondstoffen.Show();
}
}
我曾尝试编写此代码，但这会打开一个Total different Form。
答案 0 :(得分：2)
只需将 private void button1_Click(object sender, EventArgs e)
{
myForm Grondstoffen = new myForm();
Grondstoffen.Show();
}
替换为 <paper-input label="Geef je naam" value="{{naam}}"></paper-input>
<paper-input label="telefoon nummer" value="{{telnr}}"></paper-input>
<paper-button on-tap="contactToevoegen">Voeg contact toe</paper-button>
{{naam}}
{{telnr}}
<iron-ajax
id="ajax-contact-toevoegen"
method="POST"
url="/cgi-bin/contact-toevoegen.py"
handle-as="json"
on-response="contactToevoegen_ResponseHandler">
</iron-ajax>
</template>
<script>
Polymer({
is: "contact-form",
contactToevoegen: function() {
this.$.ajax-contact-toevoegen.contentType="application/json";
this.$.ajax-contact-toevoegen.body={naam: this.naam, telnr:
this.telnr};
this.$.ajax-contact-toevoegen.generateRequest();
console.log(
"Contact: "
+ this.naam
+ ", "
+ this.telnr);
}
});
</script>
</dom-module>
，例如，如果您要打开名为 myForm 的表单
If Session("LoggedOn") = "NO" Then
Response.Redirest("MainPage.aspx", False) 'False to indicate that the rest of the code in the procedure is not to be executed.
End IF