通过POST将JavaScript数组发送到PHP

时间:2017-04-23 10:43:02

标签: javascript php jquery arrays post

我正在尝试通过POST将JavaScript数组发送到PHP文件。

JS:

IDEAL
MODEL small
STACK 100h
DATASEG
;================================
filename db 'test.bmp',0

filehandle dw ?

Header db 54 dup (0)

Palette db 256*4 dup (0)

ScrLine db 320 dup (0)

ErrorMsg db 'Error', 13, 10,'$'
;================================
CODESEG
;================================
proc OpenFile

    ; Open file

    mov ah, 3Dh
    xor al, al
    mov dx, offset filename
    int 21h

    jc openerror
    mov [filehandle], ax
    ret

    openerror:
    mov dx, offset ErrorMsg
    mov ah, 9h
    int 21h
    ret
endp OpenFile
proc ReadHeader

    ; Read BMP file header, 54 bytes

    mov ah,3fh
    mov bx, [filehandle]
    mov cx,54
    mov dx,offset Header
    int 21h
    ret
    endp ReadHeader
    proc ReadPalette

    ; Read BMP file color palette, 256 colors * 4 bytes (400h)

    mov ah,3fh
    mov cx,400h
    mov dx,offset Palette
    int 21h
    ret
endp ReadPalette
proc CopyPal

    ; Copy the colors palette to the video memory
    ; The number of the first color should be sent to port 3C8h
    ; The palette is sent to port 3C9h

    mov si,offset Palette
    mov cx,256
    mov dx,3C8h
    mov al,0

    ; Copy starting color to port 3C8h

    out dx,al

    ; Copy palette itself to port 3C9h

    inc dx
    PalLoop:

    ; Note: Colors in a BMP file are saved as BGR values rather than RGB.

    mov al,[si+2] ; Get red value.
    shr al,2 ; Max. is 255, but video palette maximal

    ; value is 63. Therefore dividing by 4.

    out dx,al ; Send it.
    mov al,[si+1] ; Get green value.
    shr al,2
    out dx,al ; Send it.
    mov al,[si] ; Get blue value.
    shr al,2
    out dx,al ; Send it.
    add si,4 ; Point to next color.

    ; (There is a null chr. after every color.)

    loop PalLoop
    ret
endp CopyPal

proc CopyBitmap

    ; BMP graphics are saved upside-down.
    ; Read the graphic line by line (200 lines in VGA format),
    ; displaying the lines from bottom to top.

    mov ax, 0A000h
    mov es, ax
    mov cx,200
    PrintBMPLoop:
    push cx

    ; di = cx*320, point to the correct screen line

    mov di,cx
    shl cx,6
    shl di,8
    add di,cx

    ; Read one line

    mov ah,3fh
    mov cx,320
    mov dx,offset ScrLine
    int 21h

    ; Copy one line into video memory

    cld 

    ; Clear direction flag, for movsb

    mov cx,320
    mov si,offset ScrLine
    rep movsb 

    ; Copy line to the screen
    ;rep movsb is same as the following code:
    ;mov es:di, ds:si
    ;inc si
    ;inc di
    ;dec cx
    ;loop until cx=0

    pop cx
    loop PrintBMPLoop
    ret
endp CopyBitmap
;================================
start:
mov ax, @data
mov ds, ax
;================================

    ; Graphic mode
    mov ax, 13h
    int 10h

    ; Process BMP file
    call OpenFile
    call ReadHeader
    call ReadPalette
    call CopyPal
    call CopyBitmap

    ; Wait for key press
    mov ah,1

    int 21h
    ; Back to text mode
    mov ah, 0
    mov al, 2
    int 10h
;================================
exit:
    mov ax, 4c00h
    int 21h
    END start

test.php:

var songlist = ['song1', 'song2', 'song3'];

var sendData = function(){
    var data = songList.join(',')
    $.post('test.php', {data: data}).always(function() {
        window.location = 'test.php';
    });
}
sendData();

当sendData();指示我test.php我得到:

  

注意:未定义索引:数据

当我尝试打印或使用数据变量时,为什么数据变量没有任何值?

3 个答案:

答案 0 :(得分:5)

这不是POST请求的工作原理。阅读有关Ajax的更多信息,但就目前而言,这就是你应该如何做的。

var songlist = ['song1', 'song2', 'song3'];

var sendData = function() {
  $.post('test.php', {
    data: songlist
  }, function(response) {
    console.log(response);
  });
}
sendData();
// test.php
<?php
$songData = $_POST['data'];
print_r($songData);
?>

答案 1 :(得分:3)

1)$ .post(&#39; url&#39;) - Ajax请求由$.post()方法完成,您已将"testing.php"作为网址提供,即无效。

2)window.location =&#39; test.php&#39; - 这用于重定向到特定页面,您已重定向到'test.php',没有任何参数/数据。这就是为什么它显示&#34;注意:未定义的索引:数据&#34;

3)尝试了解ajax的工作原理。跟着它 -

var songlist = ['song1', 'song2', 'song3'];

var sendData = function() {
  $.post('test.php', {
    data: songlist
  }, function(response) {
    console.log(response);
  });
}
sendData();
// test.php
<?php
if(isset($_POST)){
    if(isset($_POST['data'])){
    $songData = $_POST['data'];
    print_r($songData);
}}
?>

答案 2 :(得分:-2)

C: