Question

请帮忙！我不明白这里的错误。为什么我会收到错误说：＆＃34;＆＃39; int＆＃39;对象不可调用＆＃34;当我输入0,1或2以外的数字？相反，它打算打印＆＃34;您输入了错误的数字，请再试一次＆＃34;然后回去问问题。

第二个问题：另外，我怎样才能改变代码，即使我输入字母字符，它也不会给我价值错误并继续重新提问？谢谢！

def player_action():        
    player_action = int(input("Enter 0 to stay, 1 to go Up, or 2 to go Down: "))

    if player_action == 0:
        print ("Thank You, you chose to stay")


    if player_action == 1:
        print ("Thank You, you chose to go up")

    if player_action == 2:
        print ("Thank You, you chose to go down")

    else:
        print ("You have entered an incorrect number, please try again")
        player_action()

player_action()

Answer 1

Pedro已回答了您的问题的第一个答案，但对于第二个答案，尝试除了声明应该解决这个问题：

编辑：对不起，我把它搞砸了......有更好的答案，但我想我应该花点时间来解决这个问题

def player_action():
    try:
        player_action_input = int(input("Enter 0 to stay, 1 to go Up, or 2 to go Down: "))
    except ValueError:
        print("Non valid value") # or somehting akin
        player_action()
    if player_action_input == 0:
        print ("Thank You, you chose to stay")
    elif player_action_input == 1:
        print ("Thank You, you chose to go up")
    elif player_action_input == 2:
        print ("Thank You, you chose to go down")
    else:
        print ("You have entered an incorrect number, please try again")
            player_action()

player_action()

Answer 2

您应该将变量名称更改为@Pedro Lobito建议，使用while循环作为@Craig建议，您还可以包含try...except语句，但不 @ polarisfox64完成它的方式，因为他把它放在了错误的位置。

以下是供您参考的完整版本：

def player_action():    
    while True:   
        try:
            user_input = int(input("Enter 0 to stay, 1 to go Up, or 2 to go Down: "))
        except ValueError:
            print('not a number')
            continue

        if user_input == 0:
            print ("Thank You, you chose to stay")          

        if user_input == 1:
            print ("Thank You, you chose to go up")

        if user_input == 2:
            print ("Thank You, you chose to go down")

        else:
            print ("You have entered an incorrect number, please try again")
            continue
        break

player_action()

Answer 3

只需将变量名player_action更改为函数的diff名称，即：

def player_action():
    user_input = int(input("Enter 0 to stay, 1 to go Up, or 2 to go Down: "))
    if user_input == 0:
        print ("Thank You, you chose to stay")
    elif user_input == 1:
        print ("Thank You, you chose to go up")
    elif user_input == 2:
        print ("Thank You, you chose to go down")
    else:
        print ("You have entered an incorrect number, please try again")
        player_action()

player_action()

Python Int对象不可调用

3 个答案:

Python Int对​​象不可调用

3 个答案:

Python Int对象不可调用