我在文本文件中有一个数独的puzzel 9x9,我想知道如何从数独的puzzel创建一个图。苏木puzzel是一个int [] []示例puzzel
0 0 0 0 9 8 0 4 5
0 0 4 3 2 0 7 0 0
7 9 0 5 0 0 0 3 0
0 0 0 9 0 0 4 0 0
0 4 5 0 0 2 8 0 0
8 7 9 6 0 4 0 1 0
0 3 0 0 7 9 0 6 4
4 5 0 2 1 3 9 0 8
0 8 7 4 6 5 0 0 0
和类Graph
class Graph
{
private int V;
private LinkedList<Integer> adj[];
Graph(int v)
{
V = v;
adj = new LinkedList[v];
for (int i=0; i<v; ++i)
adj[i] = new LinkedList();
}
void addEdge(int v,int w)
{
adj[v].add(w);
adj[w].add(v);
}
public int getV()
{
return V;
}
public LinkedList<Integer> getListAdj(int u)
{
return adj[u];
}
我编写了一个函数来从文本文件中读取puzzel并将其实现为图形
public boolean readGraph(String input_name, int result[])
{
return true;
}
但我坚持这一步。
答案 0 :(得分:-1)
这里是:
首先,我已经知道拼图是9x9,所以文本文件中的换行符对我来说毫无意义。我可以忽略它们。此外,我知道拼图的每个元素只会是一个单个字符,所以(在将文本文件放入内存后如此:Reading a plain text file in Java):
我将String puzzle
这个文本文件存入内存。现在我想像这样遍历那个字符串:
Graph graph = new Graph(81); //9x9 graph with 81 verticies
int whichVertextAreWeOn = 0;
for (int i = 0; i < puzzle.length(); i++){
char c = puzzle.charAt(i);
if(c>'0' && c > '9'){
int integer = Integer.parseInt(c);
//now I need to add this to my Graph... Saving my work now, comments are appreciated
//Turns out you simply add edges to each vertex in a graph, the vertex itself has no value...
//so I'm going to keep track of which vertex I'm on, this is starting to seem like a bad data structure for this purpose, but I shall carry on. -Adding an iterator to keep track of which vertex I'm on.
for(int w = 0; w < graph.V(); w++;){
if(vertextIsLinked(whichVertextAreWeOn, w))
graph.addEdge(whichVertextAreWeOn, w);
}
//hum... from here I need to add an edge to this vertex for each connected vertex...
}
}
private boolean vertextIsLinked(int vertexWeAreOn, int possibleVertext){
//use rules of Sukdoku to figure out if these two verticies should be linked. This would return true for any vertex in horizontal or vertical alignment to the vertexWeAreOn.
}