Question

我有一个像这样的多维数组。

[
  0 => array:3 [
    "volume" => 1272.0
    "overflow" => 0
    "deficit" => 0
  ]
  1 => array:3 [
    "volume" => 2352.0
    "overflow" => 0
    "deficit" => 0
  ]
  2 => array:3 [
    "volume" => 3144.0
    "overflow" => 0
    "deficit" => 0
  ]
  3 => array:3 [
    "volume" => 6048.0
    "overflow" => 0
    "deficit" => 0
  ]
  4 => array:3 [
    "volume" => 8952.0
    "overflow" => 0
    "deficit" => 0
  ]
]

我有$ count变量，当嵌套数组中溢出和不足都为零时，它会递增。为此，我尝试以下循环。

$keys = array_keys($waterLevels);
$count = 0;
for ($i = 0; $i < count($waterLevels); $i++){
    foreach ($waterLevels[$keys[$i]] as $key => $value)
    {
        if (($key === 'overflow' and $value == 0) and ($key === 'deficit' and $value == 0)){
            $count = $count + 1;
        }
    }
}

如果我运行这个循环，我应该将$ count值设为5.我知道'if'条件有问题。如果我单独尝试'溢出'，它就可以了。如果我添加下一个'和'条件，则不会。我在这里错过了什么逻辑？

Answer 1

只需要这么多： -

$count = 0;
foreach ($waterLevels  as $value){
    if ($value['overflow'] == 0 && $value['deficit'] == 0){
        $count = $count + 1;
    }
}
echo $count;

输出： - https://eval.in/780558

循环通过多维数组和检查条件

1 个答案: