Question

当我从我的数据库（MySQL）中选择一些数据时，它会显示除第一行之外的所有行。如何解决？

代码

Apr 21, 2017 7:21:03 AM org.apache.solr.common.SolrException log
SEVERE: org.apache.solr.common.SolrException: ERROR: [doc=livepublish:/site/components/roadmap/social-responsibility.xml] multiple values encountered for non multiValued field items.item.expiration_dt: [2015-11-19T05:00:00.000Z, 2015-11-24T05:00:00.000Z]

Answer 1

你有两个while循环。第一个循环已将光标移动到第一个记录。第二个while循环再次移动光标。建议：将表格标签和表头直接移动到If中并删除第一个循环。

Answer 2

@ user2983401指出你有两个while循环。摆脱第一个：

// Create connection
$conn = mysqli_connect($dbhost, $dbuser, $dbpass, $dbname);
// Check connection
if (!$conn) {
die("Connection failed: " . mysqli_connect_error());
}

$sql = "SELECT id, title, image, description, tekst, address, website, telephone, email, openinghours FROM ExperienceUtrecht";
$result = mysqli_query($conn, $sql);

if (mysqli_num_rows($result) > 0) {
// output data of each row
/*while($row = mysqli_fetch_assoc($result)) { Not needed*/
    echo "<table border='1'> <tr> <th>ID</th> <th>Title</th> <th>Image</th> <th>Description</th> <th>Tekst</th> <th>Address</th> <th>Website</th> <th>Telephone</th> <th>Email</th> <th>Opening Hours</th> </tr>"; 
    while($row = mysqli_fetch_array($result)) { echo "<tr>"; echo "<td>" . $row['id'] . "</td>"; echo "<td>" . $row['title'] . "</td>"; echo "<td>" . $row['image'] . "</td>"; echo "<td>" . $row['description'] . "</td>"; echo "<td>" . $row['tekst'] . "</td>"; echo "<td>" . $row['address'] . "</td>"; echo "<td>" . $row['website'] . "</td>"; echo "<td>" . $row['telephone'] . "</td>"; echo "<td>" . $row['email'] . "</td>"; echo "<td>" . $row['openinghours'] . "</td>"; echo "</tr>"; } echo "</table>";
/*} Not needed*/
} else {
echo "0 results";
}

mysqli_close($conn);
?>

Answer 3

//它会起作用。你的逻辑很好但不幸的是你做的只是一个简单的错误。你使用两个while循环来获取相同的记录。

//首先循环获取第一条记录并在内循环运行后，第二条记录和继续记录提取，并尝试打印此记录。

显示除第1行之外的所有行

3 个答案: