Question

我正在使用GraphQL js。我想在其中实现一对多关联。我有两种类型用户和 Office 。一个用户拥有很多办公室。

的用户类型：

var graphql = require('graphql');
const userType = new graphql.GraphQLObjectType({
name: 'user',
fields :()=>{
var officeType=require('./officeSchema');
return {
  _id: {
    type: graphql.GraphQLID
  },
  name: {
    type: graphql.GraphQLString
  },
  age: {
    type: graphql.GraphQLString
  },
  office:{
    type:officeType
  }
};
}
 });
module.exports=userType;

officeSchema：

const officeType = new graphql.GraphQLObjectType({
name: 'office',
fields:()=> {
var userType = require('./userSchema');
return {
  _id: {
    type: graphql.GraphQLID
  },
  room: {
    type: graphql.GraphQLString
  },
  location: {
    type: graphql.GraphQLString
  },
  users: {
    type: new graphql.GraphQLList(userType),
    resolve: (obj,{_id}) => {
     fetch('http://0.0.0.0:8082/office/user/'+obj._id, {
          method: "GET",
          headers: {
            'Content-Type': 'application/json'
          }
        })
        .then(function(res) {return res}); 
  }
  }
 };
 }
});

现在突变代码如下：

const Adduser = {
type: userType,
args: {
    name: {
        type: graphql.GraphQLString
    },
    age: {
        type: graphql.GraphQLString
    }

},
resolve: (obj, {
    input
}) => {

}
};
const Addoffice = {
type: OfficeType,
args: {
     room: {
            type: graphql.GraphQLString
        },
        location: {
            type: graphql.GraphQLString
        },
        users: {
            type: new graphql.GraphQLList(userInputType)
        }
},
resolve: (obj, {
    input
}) => {

}
};
const Rootmutation = new graphql.GraphQLObjectType({
name: 'Rootmutation',
fields: {
    Adduser: Adduser,
    Addoffice: Addoffice
}
});

此代码抛出错误

Rootmutation.Addoffice（用户:)参数类型必须是输入类型，但得到：[user]。

我想在数据库中添加实际字段以及相关表格＆＃39;但是无法解决问题。

更新

1 - 添加了GraphQLInputObjectType：

const officeInputType = new graphql.GraphQLInputObjectType({
name: 'officeinput',
fields: () => {
    return {
        room: {
            type: graphql.GraphQLString
        },
        location: {
            type: graphql.GraphQLString
        }
    }
 }
});
const userInputType = new graphql.GraphQLInputObjectType({
name: 'userinput',
fields: () => {
    return {
        name: {
            type: graphql.GraphQLString
        },
        age: {
            type: graphql.GraphQLString
        }
    }
  }
});

2 - 在AddOffice中添加了userinputtype而不是usertype。

现在错误是

 Rootmutation.Addoffice(user:) argument type must be Input Type but got: userinput.

Answer 1

问题在于您提供了userType作为Addoffice突变的参数类型之一。 userType不能是参数类型。相反，您必须使用输入类型。

有两种对象类型：输出和输入类型。您的userType和officeType是输出类型。您需要使用GraphQLInputObjectType [docs]创建输入类型。它可能会有非常相似的领域。您可以将其用作参数字段中的类型。

const userInputType = new graphql.GraphQLInputObjectType({
  name: 'UserInput',
  fields () => {
    return {
      _id: {
        type: graphql.GraphQLID
      },
      // ...
    };
  }
});

GraphQL变异中的自定义类型

1 个答案: