Question

foreach ($array_leave_dates as $emp => $leave_type) {
    foreach ($leave_type as $leave_dates) {
       if($leave_type == 'Maternity Leave'){
         unset($array_leave_dates[$leave_type]);
       }
       else{
         echo $leave_dates[$row];
       }
    }
}

在这里，我们可以获取$ leave_dates，并希望删除或取消设置leave_type =='产假'。但不可能。请帮助指出上面代码中的错误。

Answer 1

不确定您的数据源是什么样的：

<?php
// Remove the whole employee 
$employees = array(
    'emp1' => array('sick' => 'Mon - Tue'),
    'emp2' => array('bun in oven' => '2016 - 2017'),
    'emp3' => array('broken heart' => '2017 - ∞'),
);

foreach ($employees as $emp => $leave) { 

    foreach ($leave as $leaveName => $date) { 

        if($leaveName == 'bun in oven') { 
            unset($employees[$emp]); 
        }
    }
}

print_r($employees);


// OR remove only 'Maternity' from the employee but keep everything else
<?php
$employees = array(
    'emp1' => array('sick' => 'Mon - Tue', 'its friday and im not coming in' => 'Fri'),
    'emp2' => array('bun in oven' => '2016 - 2017', 'sick' => 'Thu'),
    'emp3' => array('broken heart' => '2017 - ∞'),
);

foreach ($employees as $emp => $leave) { 

    foreach ($leave as $leaveName => $date) { 

        if($leaveName == 'bun in oven') { 
            unset($employees[$emp][$leaveName]); 
        }
    }
}

print_r($employees);

Answer 2

查看//评论

foreach ($array_leave_dates as $emp => $leave_type) {
  // you treat $leave_type as array here
  foreach ($leave_type as $leave_dates) {
   // you treat $leave_type as string here
   // doesn't feel right
   if($leave_type == 'Maternity Leave') {
     // you are unsetting with a value
     //unset($array_leave_dates[ --> $leave_type <-- ]);
     // i assume you want to delete the key 
     unset($array_leave_dates[$emp]);
   }
   else{
     // $row doesn't seem to exist, looks wrong from here
     echo $leave_dates[$row];
   }
  }
}

Answer 3

如果$leave_type可以是"Maternity Leave"，那么为什么要在该字符串值中搜索$leave_dates？这个问题自然是反思的。从你有两个foreach周期并且第二个嵌入第一个周期的事实让我认为$leave_type不是你想象的那样。所以，我认为你有一个多维数组，其中外键是员工姓名或ID，内键是类型。例如：

array(
    'John Doe' => array('Sickness' => array('a', 'b', 'c')),
    'Mary Doe' => array('Sickness' => array('a', 'b', 'c'), 'Maternal Leave' => array('d', 'e'))
)

如果是这种情况，那么您需要修改周期：

foreach ($array_leave_dates as $emp => $leave) {
    if ($leave['Maternity Leave']) {
         unset($array_leave_dates[$emp]['Maternity Leave']);
    }
}

如果您想要更通用的解决方案，那么这可能会对您有所帮助：

function removeByKey(&$arr, $k) {
    if (arr[$k] !== null) {
        unset arr[$k];
    }
    foreach($arr as $key => $value) {
        if (is_array($value)) {
            $arr[$key] = removeByKey($arr[$key], $k);
        }
    }
    return $arr;
}

PHP - 基于值从多维数组中删除元素

3 个答案: