我的XML看起来像这样:
<resultset>
<datarow>
<datacol>Row 1 - Col 1</datacol>
<datacol>Row 1 - Col 2</datacol>
<datacol>Row 1 - Col 3</datacol>
...
</datarow>
...
</resultset>
...
我的问题是,如何使用此XML实现IDataReader接口?我迷路了...
我已经开发了这个:
public sealed class SybaseDataReader : IDataReader
{
private DataSet _dataSet = new DataSet();
#region IDataReader methods implementation
// ...
}
我的方式很好吗?
感谢有建设性且解释清楚的帖子。
答案 0 :(得分:4)
我写了一个简单的文件阅读器实现。您可以轻松地将其调整为读取xml文件:
public class MyFileDataReader : IDataReader
{
protected StreamReader Stream { get; set; }
protected object[] Values;
protected bool Eof { get; set; }
protected string CurrentRecord { get; set; }
protected int CurrentIndex { get; set; }
public MyFileDataReader(string fileName)
{
Stream = new StreamReader(fileName);
Values = new object[this.FieldCount];
}
请记住,IDataReader有几种方法,根据您的方案,您不需要实现这些方法。但是可能存在一些您无法避免的方法实现:
public void Close()
{
Array.Clear(Values, 0, Values.Length);
Stream.Close();
Stream.Dispose();
}
public int Depth
{
get { return 0; }
}
public DataTable GetSchemaTable()
{
// avoid to implement several methods if your scenario do not demand it
throw new NotImplementedException();
}
public bool IsClosed
{
get { return Eof; }
}
public bool NextResult()
{
return false;
}
public bool Read()
{
CurrentRecord = Stream.ReadLine();
Eof = CurrentRecord == null;
if (!Eof)
{
Fill(Values);
CurrentIndex++;
}
return !Eof;
}
private void Fill(object[] values)
{
//To simplify the implementation, lets assume here that the table have just 3
//columns: the primary key, and 2 string columns. And the file is fixed column formatted
//and have 2 columns: the first with width 12 and the second with width 40. Said that, we can do as follows
values[0] = null;
values[1] = CurrentRecord.Substring(0, 12).Trim();
values[2] = CurrentRecord.Substring(12, 40).Trim();
// by default, the first position of the array hold the value that will be
// inserted at the first column of the table, and so on
// lets assume here that the primary key is auto-generated
// if the file is xml we could parse the nodes instead of Substring operations
}
public int RecordsAffected
{
get { return -1; }
}
要实现IDataReader,还必须实现IDisposable和IDataRecord接口。
IDisposable很简单,但IDataRecord可能很痛苦。同样,在这种情况下,我们无法避免一些方法实现:
public int FieldCount
{
get { return 3;//assuming the table has 3 columns }
}
public IDataReader GetData(int i)
{
if (i == 0)
return this;
return null;
}
public string GetDataTypeName(int i)
{
return "String";
}
public string GetName(int i)
{
return Values[i].ToString();
}
public string GetString(int i)
{
return Values[i].ToString();
}
public object GetValue(int i)
{
return Values[i];
}
public int GetValues(object[] values)
{
Fill(values);
Array.Copy(values, Values, this.FieldCount);
return this.FieldCount;
}
public object this[int i]
{
get { return Values[i]; }
}
希望它有所帮助。
答案 1 :(得分:2)
将DataSet作为System.Data.IDataReader的成员。
是不合逻辑的更好地考虑XmlDocumnet,XDocument或XmlReader。
答案 2 :(得分:0)
这可能会有所帮助......
//1. Create dataset
var ds = new DataSet("A Dataset");
var table = ds.Tables.Add("A Table");
table.Columns.Add("Id", typeof(int));
table.Columns.Add("Description", typeof(string));
//2. Serialize as xml
ds.WriteXml(@"C:\temp\dataset.xml");
//3. Go look at the xml file's contents.
//Your xml needs to be translated into this schema.
//You will have to write this. (Boring transform work...)
//Dataset deserialization does not work with arbitrary xml documuents.
//4. Loading the xml file
var ds2 = new DataSet();
ds2.ReadXml(@"C:\temp\dataset.xml");
//Suggestion. Investigate using LINQ-to-xml. It would be easier to
//read the data from your xml schema. You could also load the Dataset tables row by row
//using this type of approach
//1. Load xml data into an XElement.
var element = XElement.Parse(@"<resultset>
<datarow>
<datacol>Row 1 - Col 1</datacol>
<datacol>Row 1 - Col 2</datacol>
<datacol>Row 1 - Col 3</datacol>
</datarow>
</resultset>
");
//2. Create a dataset
ds = new DataSet("A Dataset");
table = ds.Tables.Add("A Table");
table.Columns.Add("Col1", typeof(string));
table.Columns.Add("Col2", typeof(string));
table.Columns.Add("Col3", typeof(string));
//3. Walk XElements and add rows to tables
foreach (var row in element.Elements("datarow"))
{
var r = table.NewRow();
table.Rows.Add(r);
int i = 0;
foreach (var columnValue in row.Elements("datacol"))
{
r[i++] = columnValue.Value;
}
}