Question

请帮我排序数组（数组应根据sdate以及edate和sdate的差异进行排序）

输入数组对象： -

[{sdate:'03/20/2017',edate:'03/21/2017',id:1},
{sdate:'03/20/2017',edate:'03/24/2017',id:2},
{sdate:'03/20/2017',edate:'03/20/2017',id:3},
{sdate:'03/19/2017',edate:'03/20/2017',id:4}]

输出数组对象： -

[{sdate:'03/19/2017',edate:'03/20/2017',id:4},
 {sdate:'03/20/2017',edate:'03/24/2017',id:2},
 {sdate:'03/20/2017',edate:'03/21/2017',id:1},
 {sdate:'03/20/2017',edate:'03/20/2017',id:3}]

我尝试过：

 arrObj.sort(function(a,b){
    return new Date(a.sdate) - new Date(b.sdate);
 });

它只返回基于sdate的排序数组，但如果sdate相同，那么对象应首先出现，其中天数差异较大(edate -sdate)

Answer 1

这应该做的伎俩:) 这里按edate（反向）排序，如果sdates相同..

＆＃13;

Arr = [{sdate:'03/20/2017',edate:'03/21/2017',id:1},
{sdate:'03/20/2017',edate:'03/24/2017',id:2},
{sdate:'03/20/2017',edate:'03/20/2017',id:3},
{sdate:'03/19/2017',edate:'03/20/2017',id:4}];

Arr.sort(function(a, b) {
  if(a.sdate === b.sdate){
  	return new Date(b.edate) - new Date(a.edate);
  }
  return new Date(a.sdate) - new Date(b.sdate);
});

console.log(Arr);

＆＃13;

Answer 2

我的两分钱：

[{
    sdate: '03/20/2017',
    edate: '03/21/2017',
    id: 1
}, {
    sdate: '03/20/2017',
    edate: '03/24/2017',
    id: 2
}, {
    sdate: '03/20/2017',
    edate: '03/20/2017',
    id: 3
}, {
    sdate: '03/19/2017',
    edate: '03/20/2017',
    id: 4
}].sort(function(a, b) {
    var sdateA = +new Date(a.sdate)
      , sdateB = +new Date(b.sdate)
      , edateA = +new Date(a.edate)
      , edateB = +new Date(b.edate);

    return sdateA === sdateB ? edateB - edateA : sdateA - sdateB;
})

根据日期和日期差异对JavaScript对象数组进行排序

2 个答案: