var data = [
{
from: "2017-04-21T12:00:00",
to: "2017-04-22T18:00:00",
period: "2"
},
{
from: "2017-04-21T18:00:00",
to: "2017-04-22T00:00:00",
period: "3"
},
{
from: "2017-04-22T00:00:00",
to: "2017-04-22T06:00:00",
period: "0"
},
{
from: "2017-04-22T06:00:00",
to: "2017-04-22T12:00:00",
period: "1"
}];

<div data-day="today">
<p>Today</p>
<li>12:00 - 18:00: rain</li>
<li>18:00 - 00:00: clouds</li>
</div>
<div data-day="2017-04-22">
<p>22. april 2017</p>
<li>00:00 - 06:00: sun</li>
<li>06:00 - 12:00: snow</li>
</div>
&#13;
我从气象服务获取数据,每天将其分为四个时段:0, 1, 2, 4
。
句点为0
的每个对象都是新一天的开始。为此,我想以日期格式from
DD. MM. YYYY HH:MM
对于期间不是0
的对象,我只需要以时间格式显示from
:HH:MM
。我使用Momentjs来解析日期,但需要输入关于如何分组的日期。
将对象映射为可行的方式,还是有人对如何实现这一目标有任何好的建议?
第一个对象将始终是当前时段,因此可能会有所不同。
{
from: "2017-04-21T12:00:00",
to: "2017-04-22T18:00:00",
period: "2",
forecast: "rain"
},
{
from: "2017-04-21T18:00:00",
to: "2017-04-22T00:00:00",
period: "3",
forecast: "clouds"
},
{
from: "2017-04-22T00:00:00",
to: "2017-04-22T06:00:00",
period: "0",
forecast: "sun"
},
{
from: "2017-04-22T06:00:00",
to: "2017-04-22T12:00:00",
period: "1",
forecast: "snow"
},
etc...
所以为此,我想为每个新的一天输出一个新的div。直到第一个周期= 0的第一个对象可以具有数据日&#34;今天&#34;。有人能指出我正确的方向吗?
<div data-day="today">
<p>Today</p>
<li>12:00 - 18:00: rain</li>
<li>18:00 - 00:00: clouds</li>
</div>
<div data-day="2017-04-22">
<p>22. april 2017</p>
<li>00:00 - 06:00: sun</li>
<li>06:00 - 12:00: snow</li>
</div>
答案 0 :(得分:0)
您可以使用jQuery:
var firstitem = $.grep(allitems, item => (item.period ==0))[0]