Question

我正在尝试使用以下命令获取应用程序版本

#!/bin/sh
appVersion=$(ssh username@server find '/dir1/dir2/dir3' -type f  -name "file.json" -exec grep "version" {} \;| awk -F ': ' '{print $2}' | sed 's/\"//g')
echo $appVersion

不幸的是我得到了以下异常 find：缺少`-exec'的参数

请帮我解决此问题。

Answer 1

运行以下脚本，该脚本将按预期运行。当您通过ssh运行命令时，您应该使用单引号来执行多个命令

// This section all works fine.  Establish SSH and expect Last Login info

ssh_cmd = ssh_cmd = "ssh " + self.user + "@" + self.hostname
self.proc = pexpect.spawn(ssh_cmd)
self.proc.expect("Last login", timeout = 5)
print("SSH login successful!")
self.is_connected = True

// Problems are here.  Outside scope executes a command now by calling this:
// Let's say the command here is Sleep 5.  Or an executable ./application  
//The Pexpect below SHOULD wait until it finishes executing, but it 
doesn't Sleep for 5 seconds or wait for ./application, this expect 
line returns IMMEDIATELY every time. 

def execute_command(self, command):
    if self._is_connected:
        self.proc.sendline("command")
        self.proc.expect("username:/")

Refer this link for further details

用于显示应用程序版本号的shell脚本

1 个答案: