Question

我有一个数据库，我有两列第一列的名称：Img 第二列的名称：名称我想在Listview中显示它们显示名称没有问题但是显示图片有问题解决方案是什么？

Adbter Listview

public class adbter_listview extends ArrayAdapter<String> {

    Activity activity;
    ArrayList<Integer> icons;
    ArrayList<String> name;

    public adbter_listview(Activity activity, ArrayList<Integer> icons, ArrayList<String> name) {
        super(activity, R.layout.custom_listview, name);
        this.activity = activity;
        this.icons = icons;
        this.name = name;
    }

    @NonNull
    @Override
    public View getView(int position, View convertView, ViewGroup parent) {
        LayoutInflater inflater = activity.getLayoutInflater();
        View v = inflater.inflate(R.layout.custom_listview, parent, false);
        ImageView iv = (ImageView) v.findViewById(R.id.imageView);
        TextView tv = (TextView) v.findViewById(R.id.textView);
        iv.setImageResource(icons.get(position));
        tv.setText(name.get(position));
        return v;
    }
}

MainActivity

public class MainActivity extends AppCompatActivity {

    ListView con;
    ArrayList<String> icons_name = new ArrayList<>();
    ArrayList<Integer> icons = new ArrayList<>();
    ArrayList<String> name = new ArrayList<>();

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);

        con = (ListView) findViewById(R.id.con);


        db connect = new db(MainActivity.this);
        SQLiteDatabase read = connect.getReadableDatabase();
        Cursor save = read.rawQuery("select image from game",null);
        save.moveToFirst();

        while(save.isAfterLast()==false)
        {
            icons_name.add(save.getString(0));
            icons.add(R.drawable.user);
            save.moveToNext();
        }


        adbter_listview adb = new adbter_listview(MainActivity.this,icons,name);
        con.setAdapter(adb);

    }

}

请帮帮我

Answer 1

使用此行获取drawable的int id

int drawableResourceId = this.getResources().getIdentifier("nameOfDrawable", "drawable", this.getPackageName());

在你的情况下

nameOfDrawable = save.getString（0）;我想

然后添加到图标arrayList，

icons.add(drawableResourceId);

希望这会奏效。

Answer 2

而不是这个

icons.add(R.drawable.user);

使用

icons.add(Integer.parseInt(save.getString(1)));

在适配器中它应该只在图像来自drawables文件夹并且像

一样使用时才有效

R.drawable.icons.get(position)

但首先从oncreate mainThread调用中删除数据库调用到另一个线程。创建新线程或使用asynctask或使用加载器。不要在mainthread中进行sqlitedatabase调用。

从sqlite中检索图像名称

2 个答案: