Question

我的文字看起来像这样：

>Sequenz: Test 1
MTEITAAMVKELRESTGAGMMDCKNALSETNGDFDKAVQLLREKGLGKAAKKADRLAAEG

>Sequenz 2 1234 Organism: Treponema
MTEITAAMVKELRESTGAGMMDCKNALSETNGDFDKAVQLLREKGLGKAAKKADRLAAEG

>Sequenz 3
MTEITAAMVKELRESTGAGMMDCKNALSETNGDFDKAVQLLREKGLGKAAKKADRLAAEG

文本块之间不一定有空行，可能是'MTEITAAMVKELRESTGAGM'的不同行数。唯一可以确定的是每行之前>。

我希望得到一个像这样的表：

HEADER 
----------
Sequenz: Test 1 
----------
Sequenz 2 1234 Organism: Treponema
----------
Sequenz 3

我试过了：

SELECT regexp_matches(regexp_split_to_table( 'text from above', '\n>'),'([A-Z,a-z,0-9]+\s)');

导致

HEADER
----------
Sequenz
----------
Sequenz
----------
Sequenz

和

Select regexp_split_to_table('text from bove', '[\\\n>+(.)\\\n]+')

导致

HEADER
----------
----------
Sequenz: Test 1 
----------
MTEITAAMVKELRESTGAGMMDCKNALSETNGDFDKAVQLLREKGLGKAAKKADRLAAEG
----------
----------
Sequenz 2 1234 Organism: Treponema 
----------
MTEITAAMVKELRESTGAGMMDCKNALSETNGDFDKAVQLLREKGLGKAAKKADRLAAEG
----------
----------
Sequenz 3 
----------
MTEITAAMVKELRESTGAGMMDCKNALSETNGDFDKAVQLLREKGLGKAAKKADRLAAEG

Answer 1

试试这个：

SELECT split_part(regexp_split_to_table(trim(leading '>' from '>Sequenz: Test 1
MTEITAAMVKELRESTGAGMMDCKNALSETNGDFDKAVQLLREKGLGKAAKKADRLAAEG

>Sequenz 2 1234 Organism: Treponema
MTEITAAMVKELRESTGAGMMDCKNALSETNGDFDKAVQLLREKGLGKAAKKADRLAAEG

>Sequenz 3
MTEITAAMVKELRESTGAGMMDCKNALSETNGDFDKAVQLLREKGLGKAAKKADRLAAEG'), E'>'),E'\n', 1) AS res

如果要保留第一个空行，请删除trim()函数。

演示：http://rextester.com/LQXY98290

从特定字符后的文本中提取每一行，并使用postgres将结果提取到表中

1 个答案: