Question

我最近用几个新表更改了我的数据库更新，并且无法从三个不同的表中获取（选择）数据有4家商店相互交换库存，它被记录在数据库中。

表'sites'有商店ID和名称信息。

CREATE TABLE `sites` (
`id` int(10) NOT NULL,
`name` varchar(35) NOT NULL
)

表' stock_exchange_new '包含有关库存转移日期的信息商店，商店等。

CREATE TABLE `stock_exchange_new` (
`id` int(11) NOT NULL,
`transfer_date` date NOT NULL,
`from_site` int(11) NOT NULL,
`to_site` int(11) NOT NULL,
`transfer_ref` varchar(255) NOT NULL,
`note` varchar(300) NOT NULL,
`added_by` int(11) NOT NULL,
`added_at` datetime NOT NULL,
`edited_by` int(11) NOT NULL,
`edited_at` datetime NOT NULL
)

表' stock_item_txns '包含有关项目的信息交换/转移：

CREATE TABLE `stock_item_txns` (
`id` int(11) NOT NULL,
`stock_exchange_id` int(11) NOT NULL,
`item_id` int(11) NOT NULL,
`units_per_ctn` int(11) NOT NULL,
`qty` decimal(10,2) NOT NULL,
`ctn_price` decimal(10,2) NOT NULL,
`total_price` decimal(10,2) NOT NULL
)

现在，对于一个特定的商店，我需要显示的数据与自身比较，例如：对于商店1，它应该是这样的：

Store Name      Total_Sent        Total_Received
Store2          500                200
Store3          490                580
Store4          300                400

到目前为止试过......

SELECT GREATEST(s1.name, s2.name) AS from_store,
  LEAST(s1.name, s2.name) AS to_store,
  SUM(CASE WHEN s1.name < s2.name THEN si.total_price ELSE 0 END) AS received,
  SUM(CASE WHEN s1.name > s2.name THEN si.total_price ELSE 0 END) AS sent
FROM stock_exchange_new se
INNER JOIN sites s1
ON se.from_site = s1.id
INNER JOIN sites s2
ON se.to_site = s2.id
INNER JOIN stock_item_txns si
ON se.id = si.stock_exchange_id
GROUP BY GREATEST(se.from_site, se.to_site),
LEAST(se.from_site, se.to_site)
HAVING MAX(GREATEST(se.from_site, se.to_site)) = '1'

以下是fiddle，以便更好地理解。

Answer 1

利用几个子查询，类似这样（未经测试）： -

SELECT s2.name AS 'Store Name',
        from_site_total,
        to_site_total
FROM sites s1
CROSS JOIN sites s2
LEFT OUTER JOIN
(
    SELECT from_site,
            to_site, 
            SUM(stock_item_txns.total_price) AS from_site_total
    FROM stock_exchange_new
    INNER JOIN stock_item_txns ON stock_exchange_new.id = stock_item_txns.stock_exchange_id
    GROUP BY from_site,
            to_site
) sub_from_site
ON s1.id = sub_from_site.from_site
AND s2.id = sub_from_site.to_site
LEFT OUTER JOIN
(
    SELECT to_site,
            from_site,
            SUM(stock_item_txns.total_price) AS to_site_total
    FROM stock_exchange_new
    INNER JOIN stock_item_txns ON stock_exchange_new.id = stock_item_txns.stock_exchange_id
    GROUP BY to_site,
            from_site
) sub_to_site
ON s1.id = sub_to_site.to_site
AND s2.id = sub_to_site.from_site
WHERE s1.name = 'Store1'
AND s2.name != 'Store1'

MYSQL加入以获取特定格式的数据

1 个答案: