由于某种原因,我的jQuery没有接受#betButton点击/提交,任何人都知道为什么?在过去的一两个小时里一直试图修复它而没有运气。任何帮助将不胜感激。 :)
$(function() {
$("#betButton").on('submit', function(e) {
e.preventDefault();
var $form = $(this),
data = "betAmount=" + $form.find("#betAmount").val() + "choice=" + $('input[name=choice]:checked').val(),
url = $form.attr("action");
if($.trim($form.find("#betAmount").val()) === ''){
}else{
$.ajax({
type: "POST",
url: url,
data: data,
success: function(response){
//$form.find("#betAmount").attr("disabled", true);
//$form.find('#betButton').attr("disabled", true);
//$("input[type=radio]").attr('disabled', true);
if(repsonse.indexOf("Bet already made") >= 0){
$('#mMessage').find('.modal-content').val("You've already placed your bet.");
$('#mMessage').modal('show');
}else{
$('#mMessage').find('.modal-content').val("Your bet has been placed successfully.");
$('#mMessage').modal('show');
}
}
})
}
});
});
<form action="/models/coinroulette.php" method="POST">
<div class="panel panel-default">
<div class="panel-heading panelHNew">Make a Bet</div>
<div class="panel-body">
<div class="form-group padding-top">
<p class="padding-left">Enter in a bet amount and select a coin (heads or tails).</p>
<div class="col-lg-8">
<div class="input-group">
<span class="input-group-addon">
<i class="glyphicon glyphicon-gift"></i>
</span>
<input class="form-control" placeholder="Bet Amount" id="betAmount" name="betAmount" type="number" autofocus>
</div>
</div>
<div class="col-lg-4">
<label style="margin-left: -10px;">
<input type="radio" name="choice" value="heads" class="noRButton"/>
<img class="profile-img" src="../resources/img/coinroulette/heads.png" alt=""/>
</label>
<label>
<input type="radio" name="choice" value="tails" class="noRButton"/>
<img class="profile-img" src="../resources/img/coinroulette/tails.png" alt=""/>
</label>
</div>
<div class="col-lg-12">
<div class="form-group padding-top">
<button type="submit" id="betButton" class="btn btn-lg btn-primary btn-block">Place Bet</button>
</div>
</div>
</div>
</div>
</div>
</form>
答案 0 :(得分:0)
按钮没有提交事件。
将事件移至表单:
$("form").on('submit', function(e) {
...
});
您还需要进行拼写更正(repsonse
而不是response
):
if(repsonse.indexOf("Bet already made") >= 0){
并且不需要使用find()
来获取具有ID的元素。变化:
$form.find("#betAmount").val()
......来:
$("#betAmount").val()