我有array2
生成的具有不同元素名称的数据框。
lapply
另一组格式相似,在Group
下由2指定head(df1)
$Sample1
G1 G2 Group
1 1.016673 -1.04402692 1
2 1.019958 -0.86763046 1
3 1.033050 -1.09717438 1
4 1.036969 0.26971351 1
5 1.044059 1.73402959 1
$Sample2
G1 G2 Group
1 1.413218 0.22466456 1
2 1.413339 -0.91755436 1
3 1.415782 -0.23471118 1
4 1.434750 -0.77498973 1
5 1.436905 0.76642626 1
我的目标是通过元素名称将它们组合/合并在一起,例如head(df2)
$Sample1
G1 G2 Group
1 1.053269 -1.04460950 2
2 1.059461 -0.86711232 2
3 1.072446 -1.09748431 2
4 1.078763 0.26785751 2
5 1.038325 1.73818175 2
$Sample2
G1 G2 Group
1 1.438067 0.22933986 2
2 1.856085 -0.91988726 2
3 1.415782 -0.23405677 2
4 1.434750 -0.77406530 2
5 1.436905 0.76078091 2
和Sample1
。
Sample2
我无法弄清楚如何做到这一点。有人能帮助我吗?谢谢!
答案 0 :(得分:3)
也许尝试mapply
和rbind
:
a1 <- list(mtcars[1:5,],mtcars[6:10,])
a2 <- list(mtcars[11:15,],mtcars[16:20,])
> mapply(FUN = rbind,a1,a2,SIMPLIFY = FALSE)
[[1]]
mpg cyl disp hp drat wt qsec vs am gear carb
Mazda RX4 21.0 6 160.0 110 3.90 2.620 16.46 0 1 4 4
Mazda RX4 Wag 21.0 6 160.0 110 3.90 2.875 17.02 0 1 4 4
Datsun 710 22.8 4 108.0 93 3.85 2.320 18.61 1 1 4 1
Hornet 4 Drive 21.4 6 258.0 110 3.08 3.215 19.44 1 0 3 1
Hornet Sportabout 18.7 8 360.0 175 3.15 3.440 17.02 0 0 3 2
Merc 280C 17.8 6 167.6 123 3.92 3.440 18.90 1 0 4 4
Merc 450SE 16.4 8 275.8 180 3.07 4.070 17.40 0 0 3 3
Merc 450SL 17.3 8 275.8 180 3.07 3.730 17.60 0 0 3 3
Merc 450SLC 15.2 8 275.8 180 3.07 3.780 18.00 0 0 3 3
Cadillac Fleetwood 10.4 8 472.0 205 2.93 5.250 17.98 0 0 3 4
[[2]]
mpg cyl disp hp drat wt qsec vs am gear carb
Valiant 18.1 6 225.0 105 2.76 3.460 20.22 1 0 3 1
Duster 360 14.3 8 360.0 245 3.21 3.570 15.84 0 0 3 4
Merc 240D 24.4 4 146.7 62 3.69 3.190 20.00 1 0 4 2
Merc 230 22.8 4 140.8 95 3.92 3.150 22.90 1 0 4 2
Merc 280 19.2 6 167.6 123 3.92 3.440 18.30 1 0 4 4
Lincoln Continental 10.4 8 460.0 215 3.00 5.424 17.82 0 0 3 4
Chrysler Imperial 14.7 8 440.0 230 3.23 5.345 17.42 0 0 3 4
Fiat 128 32.4 4 78.7 66 4.08 2.200 19.47 1 1 4 1
Honda Civic 30.4 4 75.7 52 4.93 1.615 18.52 1 1 4 2
Toyota Corolla 33.9 4 71.1 65 4.22 1.835 19.90 1 1 4 1
purrr 中的等同(我认为)将为map2(a1,a2,rbind)
。