Question

我是Java新手，非常感谢任何人都能给我的帮助

我需要编写一个程序，要求用户输入一个包含5个字符的字符串，例如asdfg，然后将它们转换为单词，例如'apple spinach dog fish goat'。（这些是用户输入的字母）

我一直在尝试将这些输入到数组中，并从中更改元素，但我不完全确定如何。

这是我到目前为止的代码

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感谢任何人的帮助！

Answer 1

将所有这些东西放在地图中会更好。

Map<Character,String> dataMap = new HashMap<Character,String>();
dataMap.put('a',"apple");
dataMap.put('s',"spinach");
dataMap.put('d',"dog");
dataMap.put('f',"fish");
dataMap.put('g',"goat");

现在按所需顺序打印数据，如下所示

//Print all the array elements
    for (int i = 0; i < myList.length; i++) {
        System.out.println(dataMap.get(myList.charAt(i)) + " ");
    }

Answer 2

现在代码存在一些问题。首先，您需要将收到的字符串转换为字符数组。然后，要使用列表实现，您必须遍历两个列表，以使每个输入字符与以该字母开头的单词匹配。

更好的选择是将字母配对放在地图中并以这种方式检索它们。

最后，您可能不想使用＆＃34; System.out.println＆＃34;，因为这样您就可以在不同的行上获得结果。相反，使用＆＃34; System.out.print。＆＃34;

public static void main(String[] args) {
    Scanner scan = new Scanner(System.in);

    System.out.println("Please enter the details of your order");
    String myString = scan.nextLine();
    char[] myChars = myString.toCharArray();

    Map<Character, String> map = new HashMap<>();
    map.put('a', "apple");
    map.put('s', "spinache");
    map.put('d', "dog");
    map.put('f', "fish");
    map.put('g', "goat");


    //Print all the array elements
    for (int i = 0; i < myChars.length; i++) {
        System.out.print(map.get(myChars[i]) + " ");
    }
}

Answer 3

问题不是很清楚。但这是解决问题的简单方法

public static void main (String[] args) throws java.lang.Exception
    {
        // your code goes here
         Scanner scan = new Scanner(System.in);

        System.out.println("Please enter the details of your order");
        String myList = scan.nextLine();

        for(int i=0;i<myList.length();i++){
            switch(myList.charAt(i)){
                case 'a':System.out.println("Apple");
                break;
                case 's':System.out.println("Spinach");
                break;
                case 'd':System.out.println("Dog");
                break;
                case 'f':System.out.println("Fish");
                break;
                case 'g':System.out.println("Goat");
                break;
                default: System.out.println("Nothing..");
                     break;
            }
        }
    }

Answer 4

试试这个：

['/Users/austinjohnson/Desktop/streakscraper', '/usr/local/Cellar/python3/3.6.1/Frameworks/Python.framework/Versions/3.6/lib/python36.zip', '/usr/local/Cellar/python3/3.6.1/Frameworks/Python.framework/Versions/3.6/lib/python3.6', '/usr/local/Cellar/python3/3.6.1/Frameworks/Python.framework/Versions/3.6/lib/python3.6/lib-dynload', '/usr/local/lib/python3.6/site-packages']
Traceback (most recent call last):
  File "/Users/austinjohnson/Desktop/streakscraper/login.py", line 6, in <module>
    from selenium import webdriver 
ImportError: cannot import name 'webdriver'
[Finished in 0.1s with exit code 1]
[cmd: ['/usr/local/bin/python3', '-u', '/Users/austinjohnson/Desktop/streakscraper/login.py']]
[dir: /Users/austinjohnson/Desktop/streakscraper]
[path: /usr/bin:/bin:/usr/sbin:/sbin]

我认为使用地图解决这个问题可能更合适。

String inputString = "asdfg"; //your scan.next();

//use array constructor
String [] myList = {"apple", "spinach", "dog", "fish", "goat"};
//start our result string as empty
String result = "";
//for each letter of our input string...
for(char letter: inputString.toCharArray()){
    //...check each of the words in my list to see if they start with that letter
    for(String word: myList){
        if(word.toCharArray()[0] == letter){
            result = result + " " + word;
        }
    }
}
System.out.println(result);  //prints "apple spinach dog fish goat"

然后你也可以使用reduce来实现这个功能。

//build a map
String inputString = "asdfg"; //your scan.next();
Map<String, String> myMap = new HashMap<>();
myMap.put("a", "apple");
myMap.put("s", "spinach");
myMap.put("d", "dog");
myMap.put("f", "fish");
myMap.put("g", "goat");
//initilize our result string
String result = "";
//split the string and get our values straight from the map
for(String letter: inputString.split("")){
    result = result + " " + myMap.get(letter);
}
System.out.println(result); //" apple spinach dog fish goat"

Java - 将一串字母转换为等效的单词

4 个答案: