Question

我有一个我编写的python脚本，我根据需要使用来自dkpg -l命令的perl解析大部分输出。我想要输出的是创建一个json结构输出文件，如下所示。

我是python的新手，所以在这里寻找一些关于什么是我最好的选项以产生这样一个具有数组结构的json文件的技巧？

Json文件

{

 "hostname": "xyz-abc-m001",
 "publicIP": "111.00.00.xxx",
 "privateIP": "10.xxx.xx.61",
 "kernal": "4.4.0-72-generic #93-Ubuntu",
 "package": [
   { "name":"nfs-common", "installed":"1:1.2.8-9ubuntu12", "available":"1:1.2.8-9ubuntu12.1" },
   { "name":"grub-common", "installed":"2.02~beta2-36ubuntu3.8", "available":"2.02~beta2-36ubuntu3.9" },
   { "name":"wget", "installed":"1.17.1-1ubuntu1.1", "available":"1.17.1-1ubuntu1.2" }

 ]

}

Python脚本

import socket
import os
import subprocess
from subprocess import Popen, PIPE


#Getting Hostname of the machine
hostname=socket.gethostname()

#Getting private IP of the machine on eth0 
f = os.popen(" ip addr show eth0 | grep -Po 'inet \K[\d.]+' ")
private_ip=f.read()

#Getting public IP of the machine on eth1 
f = os.popen(" ip addr show eth1 | grep -Po 'inet \K[\d.]+' ")
public_ip=f.read()

#Getting currently running linux kernal
f = os.popen(" uname -a | awk '{print $3, $4}' ")
running_kernal=f.read()        


pipe = Popen(" apt-get --just-print upgrade 2>&1 | perl -ne 'if (/Inst\s([\w,\-,\d,\.,~,:,\+]+)\s\[([\w,\-,\d,\.,~,:,\+]+)\]\s\(([\w,\-,\d,\.,~,:,\+]+)\)? /i) {print \"$1 $2 $3\n\"} ' ", shell=True, stdout=PIPE)

for line in pipe.stdout:
    parts = line.split() # split line into parts
    if len(parts) > 1:   # if at least 2 parts/columns
        print "Hostname = %s  PublicIP = %s PrivateIP = %s Package name = %s INSTALLED  = %s  AVAILABLE = %s kernal = %s " % (hostname, public_ip, private_ip, parts[0], parts[1], parts[2], running_kernal)

Answer 1

那里有一个图书馆！

import json

使用此功能，您可以获取数据结构...并将其转换为json！

data = [1, 2, 3, {"hello world":42}]
myjson = json.dumps(data)

......基本上就是这样。使用json.loads和json.load分别从json类和json文件加载您可以在 this website

了解更多信息

P.S。如果要使用缩进打印，请尝试

some_dictionary = {'hostname':hostname, 'PublicIP':publicIp, etc}
print(json.dumps(some_dictionary, indent=4))`

从我的python解析器脚本创建Json输出

1 个答案: