我有两张桌子。一种格式如下:
Id | FieldName | Value
0 | field1 | 0
1 | field2 | 0
2 | field3 | 0
第二种格式如下:
Id | field1 | field2 | field3
0 | 1 | 1 | 1
1 | 1 | 1 | 1
2 | 1 | 1 | 1
我需要更新第二个表,以便将1的值更改为0,其中fieldname列值与第二个表中的列值匹配。所以决赛桌应该是这样的:
Id | field1 | field2 | field3
0 | 0 | 1 | 1
1 | 1 | 0 | 1
2 | 1 | 1 | 0
答案 0 :(得分:0)
试试这个: -
Select a.id,
Case when (fieldName='field1' and field1=1) then value else field1 end as field1,
Case when (fieldName='field2' and field2=1) then value else field2 end as field2,
Case when (fieldName='field3' and field3=1) then value else field3 end as field3
from
table2 a
inner join
table1 b
on a.id=b.id
感谢: - )