Question

我想制作一份报告，说明项目是否在一年中的每个月完成。完成项目的数量并不重要，只要至少是否已完成项目。

with project_data as(
select '123' account, 'Started' status, to_date('01/01/2017','MM/DD/YY') 
sale_date from dual union all
select '123' account, 'Complete' status, to_date('01/15/2017','MM/DD/YY') 
sale_date from dual union all
select '123' account, 'Started' status, to_date('02/01/2017','MM/DD/YY') 
sale_date from dual union all
select '123' account, 'Complete' status, to_date('04/12/2017','MM/DD/YY') 
sale_date from dual union all
select '123' account, 'Complete' status, to_date('04/16/2017','MM/DD/YY') 
sale_date from dual)

从这个例子中我希望输出如下：

Account Completed Month Year
123     Yes       1     2017
123     No        2     2017
123     No        3     2017
123     Yes       4     2017

Answer 1

SELECT YEAR,
       MONTH,
       ACCOUNT,
       CASE WHEN COMPLETED > 0 THEN 'YES' ELSE 'NO' END AS AT_LEAST_ONE_COMP
  FROM (  SELECT EXTRACT (YEAR FROM SALE_DATE) AS YEAR,
                 EXTRACT (MONTH FROM SALE_DATE) AS MONTH,
                 ACCOUNT,
                 SUM (CASE WHEN STATUS = 'Complete' THEN 1 ELSE 0 END)
                    AS completed
            FROM MY_TABLE
        GROUP BY EXTRACT (YEAR FROM SALE_DATE),
                 EXTRACT (MONTH FROM SALE_DATE), 
                 ACCOUNT)

Answer 2

Oracle安装程序：

CREATE TABLE table_name ( account, status, sale_date ) AS
  select '123', 'Started',  DATE '2017-01-01' from dual union all
  select '123', 'Complete', DATE '2017-01-15' from dual union all
  select '123', 'Started',  DATE '2017-02-01' from dual union all
  select '123', 'Complete', DATE '2017-04-12' from dual union all
  select '123', 'Complete', DATE '2017-04-16' from dual union all
  select '456', 'Complete', DATE '2017-03-28' from dual;

<强>查询：

SELECT ACCOUNT,
       MONTH,
       CASE COUNT( CASE status WHEN 'Complete' THEN 1 END )
         WHEN 0
         THEN 'No'
         ELSE 'Yes'
       END AS Completed
FROM   ( SELECT ADD_MONTHS( TRUNC( SYSDATE, 'YEAR' ), LEVEL - 1 ) AS month
         FROM   DUAL
         CONNECT BY ADD_MONTHS( TRUNC( SYSDATE, 'YEAR' ), LEVEL - 1 ) <= SYSDATE )
       LEFT OUTER JOIN
       table_name t
       PARTITION BY ( t.account )
       ON ( month <= sale_date AND sale_date < ADD_MONTHS( month, 1 ) )
GROUP BY Account, Month
ORDER BY Account, Month;

<强>输出：

ACC MONTH               COM
--- ------------------- ---
123 2017-01-01 00:00:00 Yes
123 2017-02-01 00:00:00 No 
123 2017-03-01 00:00:00 No 
123 2017-04-01 00:00:00 Yes
456 2017-01-01 00:00:00 No 
456 2017-02-01 00:00:00 No 
456 2017-03-01 00:00:00 Yes
456 2017-04-01 00:00:00 No

如何使用Oracle SQL为每个月选择一列的最大值

2 个答案: