在python中水平对齐条形图图例

Question

我使用以下代码制作了一个多轴图，我无法按照自己的意愿排列图例。我的图表代码如下：

import matplotlib.pyplot as plt
import numpy as np

x = np.arange(4)

y = [5, 7, 4, 9]
z = [9, 3, 5, 6]
r = [30, 40, 45, 37]


fig,ax = plt.subplots()

abc = ax.bar(x,y,0.25 )
cde = ax.bar(x+0.25,z,0.25)

ax.legend((abc[0], cde[0]), ('y', 'z'),bbox_to_anchor=(0., 1.02, 1, .102) , borderaxespad=0.)
ax.set_xticks(x + 0.25 / 2)
ax.set_xticklabels(('A', 'B', 'C', 'D'))

ax2 = ax.twinx()
efg = ax2.plot(x+0.25/2,r,color = 'black',label = "r")
ax2.legend(bbox_to_anchor=(0.11,1.07) , borderaxespad=0.)

plt.show()

它显示的图表就像这个。

右上方的图例垂直对齐，但我希望它们水平对齐。我找不到任何关于此的文件。我希望它们如下图所示。

由于

Answer 1

您需要使用ncol参数，该参数设置legend中要使用的列数，例如ncol=2会给你两列。

ax.legend(..., ncol=2)

然后，您可以使用loc参数和bbox_to_anchor查看how to place the legend，以找到合理的参数并使两个图例相互对齐：

import matplotlib.pyplot as plt
import numpy as np

x = np.arange(4)

y = [5, 7, 4, 9]
z = [9, 3, 5, 6]
r = [30, 40, 45, 37]


fig,ax = plt.subplots()

abc = ax.bar(x,y,0.25 )
cde = ax.bar(x+0.25,z,0.25)

ax.legend((abc[0], cde[0]), ('y', 'z'),loc="lower right", bbox_to_anchor=(1., 1.02) , borderaxespad=0., ncol=2)
ax.set_xticks(x + 0.25 / 2)
ax.set_xticklabels(('A', 'B', 'C', 'D'))

ax2 = ax.twinx()
efg = ax2.plot(x+0.25/2,r,color = 'black',label = "r")
ax2.legend(bbox_to_anchor=(0,1.02),loc="lower left", borderaxespad=0.)

plt.show()