Question

我试图为git编写一个prepare-commit-msg钩子。该脚本应执行以下步骤：

获取当前的git分支名称（工作）
提取issue-id（不工作）
检查issue-id是否已在提交消息中
如果没有，请在提交消息

[issue-id]

issue-id具有此模式[a-zA-Z]+-\d+，分支名称应为feature/issue-id-my-small-description。

但是现在，提取部分还不行......

这是我的prepare-commit-msg脚本：

# Regex used to extract the issue id
REGEX_ISSUE_ID="s/([a-zA-Z]+-\d+)//"

# Find current branch name
BRANCH_NAME=$(git symbolic-ref --short HEAD)

# Extract issue id from branch name
ISSUE_ID= $BRANCH_NAME | sed -r $REGEX_ISSUE_ID

# Check if the issue id is already in the msg
ISSUE_IN_COMMIT=$(grep -c "\[$ISSUE_ID\]" $1)

# Check if branch name is not null and if the issue id is already in the commit msg
if [ -n "$BRANCH_NAME" ] && ! [[ $ISSUE_IN_COMMIT -ge 1 ]]; then 
  # Prefix with the issue id surrounded with brackets
  sed -i.bak -e "1s/^/[$ISSUE_ID] /" $1
fi

编辑以添加输入/输出示例

输入$1是git commit消息，类似于

fix bug on login

或

fix MyIssue-234 which is a bug on login

输出应该是带有问题ID的输入，即：

[MyIssue-123] fix bug on login

Answer 1

我不确定你做了什么以及为什么这样做，但这是我通过修复我认为在你的代码中纠正的最接近的方式：

# Regex used to extract the issue id
REGEX_ISSUE_ID="s/\[([a-zA-Z]+-[0-9]+)\].*/\1/"

# Find current branch name
BRANCH_NAME=$(git symbolic-ref --short HEAD)
if [[ -z "$BRANCH_NAME" ]]; then
    echo "No brach name... "; exit 1
fi

# Extract issue id from branch name
ISSUE_ID=$(echo "$BRANCH_NAME" | sed -r "$REGEX_ISSUE_ID")

# Check if the issue id is already in the msg
ISSUE_IN_COMMIT=$(echo "$@" | grep -c "^\[*$ISSUE_ID\]*")

# Check if branch name is not null and if the issue id is already in the commit msg
if [[ -n "$BRANCH_NAME" ]]; then
    if [[ $ISSUE_IN_COMMIT -gt 0 ]]; then 
        shift # Drop the issue if from the msg
    fi
    # Prefix with the issue id surrounded with brackets
    MESSAGE="[$ISSUE_ID] $@"
fi

echo "$MESSAGE"

其中$@是您在＆＃34;修复＆＃34;之后提供的所有字词。（例如"$@" = "bug" "on" "login"）。其余的我希望您在将其与原始代码进行比较后了解。

无法使用正则表达式提取子字符串

1 个答案: