Question

我试图让所有项目＆＃39;来自下表的ID，条件为uid =＆＃39; 1＆＃39;和月份=＆＃39;八月＆＃39;和年=＆＃39; 2016＆＃39;

date               |     uid    |     project
-------------------------------------------
Wed, 01 Aug 2016   |     1      |      11
Tue, 15 Aug 2016   |     2      |      11
Mon, 31 Aug 2016   |     1      |      11
Thu, 05 Sep 2016   |     1      |      12
Sat, 10 Sep 2016   |     2      |      12
Mon, 12 Feb 2017   |     3      |      12
Tue, 31 Feb 2017   |     1      |      13
Wed, 31 Mar 2017   |     2      |      13
Fri, 31 Mar 2017   |     3      |      13
Thu, 31 Mar 2017   |     1      |      14

以下是我使用的查询

SELECT project FROM logs where uid="1" AND MONTHNAME(STR_TO_DATE(date,'%W, %d %M %Y'))="August" AND YEAR(STR_TO_DATE(date,'%W, %d %M %Y'))="2016";

但它也正在返回其他月份的记录。我在这做错了什么？

Answer 1

我只会使用like：

SELECT project
FROM logs 
WHERE uid = 1 AND 
      date LIKE '% Aug 2016';

不要将日期/时间值存储为字符串。如果你这样做，不要打电话给他们＆＃34;约会＆＃34;，称他们为＆＃34; datestr＆＃34;防止意外错误。但如果它是一个字符串，你可以像对待字符串一样对待它。

Answer 2

SELECT project 
FROM logs 
WHERE uid= 1
AND MONTHNAME(STR_TO_DATE(date,'%W, %d %M %Y'))= 'August' 
AND YEAR(STR_TO_DATE(date,'%W, %d %M %Y'))= 2016
;

Mysql获取记录WHERE MONTHNAME（）＆amp; YEAR（）等于一个值

2 个答案: