Question

这是我的酒店流程 我想显示数据库中的数据，但有一些条件。比如价格。我想显示高于我们从表单函数提示的价格的数据。

<!DOCTYPE html>
<html>
<head>
    <title>Hotel</title>
</head>
    <body>
        <?php
    include 'dbh.php';
        
    $price = $_POST['price'];
        
    $query = "SELECT * FROM hotel";
    $result = mysqli_query($conn, $query);
        ?>
    
    <table id="Htable">
    <tr class="header">
        <th style ="width:60%;">Price</th>
        <th style ="width:40%;">Hotel Name</th>
    </tr>
     <? while($rows = mysqli_fetch_array($result))
    {
        <? if($price > $rows['h_price'])
        { ?>
                 $h_price = $rows['h_price'];
                 $n_hotel = $rows['n_hotel']; 	
            ?>
             <tr>
                <td> <?= $h_price ?> </td> 
                <td> <?= $n_hotel ?> </td>
             </tr>
        <? } ?>
             <? } ?>
    </table>
    </body>
</html>

这是我提示价格的表单页面这个文件我想做表格为DSS做过滤系统。

<!DOCTYPE html>
<html>

<head>
  PHP
</head>

<body>
  <form action="hotelprocess.php" method="POST">
    <p>
      <label>Price:</label>
      <input type="text" id="price" name="price" />
    </p>
    <p>
      <input type="submit" name="hotel" />
    </p>
  </form>
</body>

</html>

这是数据库连接

<?php
//connect with database
$conn=mysqli_connect("localhost", "root", "", "register");
if(!$conn){
    die("connection failed:".mysqli_connect_error());
}

?>

Answer 1

通过sql语句检查价格条件。

<?php
     include 'dbh.php';

    if(isset($_POST['price'])){  
        $price = $_POST['price'];

        $query = "SELECT * FROM hotel where h_price < '" .$price. "' ";
        $result = mysqli_query($conn, $query);
    }else{
        $query = "SELECT * FROM hotel";
        $result = mysqli_query($conn, $query);
    }   

    ?>

您可以显示这样的表格。

<?
 while($rows = mysqli_fetch_array($result))
    {


                 $h_price = $rows['h_price'];
                 $n_hotel = $rows['n_hotel'];   

         echo   ' <tr>
                <td> ='; echo $h_price; echo'  </td> 
                <td> ='; echo $n_hotel; echo'  </td>
             </tr>';

     } 

?>

我不知道如何修复PHP和PHPmyAdmin中的错误

1 个答案: