我的项目文件夹包含:
Makefile README.md component/ driver/ service/ vendor/ worker/
我想在所有测试文件上运行go test
,例如除{vendor}中的测试文件之外的foobar_test.go
个文件。我最接近成功的是go test ./...
,但其中包括供应商测试文件。
我在文档中看到您可以将正则表达式传递给-run
选项,但我无法正常工作。例如,我尝试了go test ./*
,但我得到了一堆can't load package errors
。
最好的方法是什么?
答案 0 :(得分:33)
-run
模式仅与测试标识符(不是文件名)匹配;原则上你可以这样做:
go test -run TestFoo
但是当您必须将Foo
添加到您可能不想要的所有测试功能名称时。
通常的做法是:
go test $(go list ./... | grep -v /vendor/)
有a lengthy discussion at GitHub about it。最终改变了after another lengthy discussion。
从Go 1.9开始,vendor
目录会自动排除。现在,您可以直接输入:
go test ./...
答案 1 :(得分:3)
cmd/go: exclude vendor dir from matching
...
#19090[go] cmd/go: exclude vendored packages from ... matches
By overwhelming popular demand, exclude vendored packages from ... matches, by making ... never match the "vendor" element above a vendored package. go help packages now reads: An import path is a pattern if it includes one or more "..." wildcards, each of which can match any string, including the empty string and strings containing slashes. Such a pattern expands to all package directories found in the GOPATH trees with names matching the patterns. To make common patterns more convenient, there are two special cases. First, /... at the end of the pattern can match an empty string, so that net/... matches both net and packages in its subdirectories, like net/http. Second, any slash-separted pattern element containing a wildcard never participates in a match of the "vendor" element in the path of a vendored package, so that ./... does not match packages in subdirectories of ./vendor or ./mycode/vendor, but ./vendor/... and ./mycode/vendor/... do. Note, however, that a directory named vendor that itself contains code is not a vendored package: cmd/vendor would be a command named vendor, and the pattern cmd/... matches it. Fixes #19090.
go / go / fa1d54c2edad607866445577fe4949fbe55166e1
commit fa1d54c2edad607866445577fe4949fbe55166e1 Wed Mar 29 18:51:44 2017 +0000
尝试在提示处运行go test ./...
或等待Go1.9。