关于旋转的快速问题。我有以下数据:
c1 | c2 | c3 | c4 | c5
pk1 | r12 | r13 | r14 | r15
pk2 | r22 | r23 | r24 | r25
pk3 | r32 | r33 | r34 | r35
我想将其旋转如下
[c1] | pk1 | pk2 | pk3
c2 | r12 | r22 | r32
c3 | r13 | r23 | r33
c4 | r14 | r24 | r34
c5 | r15 | r25 | r35
在我的示例中,case列c1是主键。 提前感谢您的帮助。
PS:在那之前我会再给它一次。
答案 0 :(得分:1)
你可以UNPIVOT
然后PIVOT
表。
这是hardcode
版本。
DECLARE @SampleData AS TABLE
(
c1 varchar(10),
c2 varchar(10),
c3 varchar(10),
c4 varchar(10),
c5 varchar(10)
)
INSERT INTO @SampleData
VALUES
('pk1', 'r12','r13','r14','r15'),
('pk2', 'r22','r23','r24','r25'),
('pk3', 'r32','r33','r34','r35')
;with pvt AS
(
SELECT c1, ColName, Value
FROM
(
SELECT * FROM @SampleData sd
) src
UNPIVOT
(
Value FOR ColName IN (c2,c3,c4,c5)
) pvt
)
SELECT ColName AS [c1], [pk1], [pk2], [pk3]
FROM
(
SELECT * FROM pvt p
) src
PIVOT
(
Max(Value) FOR c1 IN ([pk1], [pk2], [pk3])
) pvt
演示链接:Rextester
答案 1 :(得分:0)
这有点长而且难看,但它会转动你的数据。
WITH pk1 AS (
SELECT c1,c2 'pk1'
FROM Table_1
WHERE c1 = 'pk1'
UNION
SELECT c1,c3 'pk1'
FROM Table_1
WHERE c1 = 'pk1'
UNION
SELECT c1,c4 'pk1'
FROM Table_1
WHERE c1 = 'pk1'
UNION
SELECT c1,c5 'pk1'
FROM Table_1
WHERE c1 = 'pk1'),
pk1_rn AS
(SELECT ROW_NUMBER() OVER(PARTITION BY c1 ORDER BY pk1 ASC) AS Row#, pk1
FROM pk1),
pk2 AS (
SELECT c1,c2 'pk2'
FROM Table_1
WHERE c1 = 'pk2'
UNION
SELECT c1,c3 'pk2'
FROM Table_1
WHERE c1 = 'pk2'
UNION
SELECT c1,c4 'pk2'
FROM Table_1
WHERE c1 = 'pk2'
UNION
SELECT c1,c5 'pk2'
FROM Table_1
WHERE c1 = 'pk2'),
pk2_rn AS
(SELECT ROW_NUMBER() OVER(PARTITION BY c1 ORDER BY pk2 ASC) AS Row#, pk2
FROM pk2),
pk3 AS (
SELECT c1,c2 'pk3'
FROM Table_1
WHERE c1 = 'pk3'
UNION
SELECT c1,c3 'pk3'
FROM Table_1
WHERE c1 = 'pk3'
UNION
SELECT c1,c4 'pk3'
FROM Table_1
WHERE c1 = 'pk3'
UNION
SELECT c1,c5 'pk3'
FROM Table_1
WHERE c1 = 'pk3'),
pk3_rn AS
(SELECT ROW_NUMBER() OVER(PARTITION BY c1 ORDER BY pk3 ASC) AS Row#, pk3
FROM pk3)
SELECT pk1_rn.pk1,pk2_rn.pk2,pk3_rn.pk3
FROM pk1_rn
JOIN pk2_rn ON pk1_rn.Row# = pk2_rn.Row#
JOIN pk3_rn ON pk1_rn.Row# = pk3_rn.Row#