Question

我正在使用Django和Django-rest-framework，我有下一个Model和Serializer：

class Category(models.Model):
    id_category = models.UUIDField(primary_key=True, default=uuid.uuid1, editable=False)
    name = models.TextField(null=False)
    parent = models.ForeignKey('self', on_delete=models.CASCADE, null=True, blank=True, related_name='children')

class CategorySerializer(serializers.ModelSerializer):
    class Meta:
        model = Category
        fields = ('id_category', 'name', 'parent')

现在，我想创建一个类似Category.objects.filter(parent=None)的查询，返回如下内容：

[
  {
    "id_category": "UUID",
    "name": "Father",
    "childrens": [
      {
        "id_category": "UUID",
        "name": "Son",
        "childrens": [
          {
            "id_category": "UUID",
            "name": "Grandson"
          }
        ]
      }
    ]
  },
  {
    "id_category": "UUID",
    "name": "Other"
  }
]

如你所见，一个类别可能有一个父亲和许多孩子。需要帮助才能进行此查询，因为我不知道该怎么做。

Answer 1

您可以为子类别编写其他序列化程序：

class ChildrenSerializer(serializers.ModelSerializer):

    class Meta:
         model = Category
         fields = ('id_category', 'name', 'parent')

class CategorySerializer(serializers.ModelSerializer):
    children = ChildrenSerializer(many=True)

    class Meta:
        model = Category
        fields = ('id_category', 'name', 'parent', 'children')

你could also show nested models with depth option：

class CategorySerializer(serializers.ModelSerializer):

    class Meta:
        model = Category
        depth = 1
        fields = ('id_category', 'name', 'parent', 'children')

Django嵌套关系数据

1 个答案: