Mysql每年每月获取行数

Question

我试图找出每年每个月的费用总和。

我有下表＆＃39;日志＆＃39;

date               |    cost
---------------------------------
Wed, 01 Aug 2016   |    45
Tue, 15 Aug 2016   |    52
Mon, 31 Aug 2016   |    23
Thu, 05 Sep 2016   |    9
Sat, 10 Sep 2016   |    33
Mon, 12 Feb 2017   |    8
Tue, 31 Feb 2017   |    0
Wed, 31 Mar 2017   |    100
Fri, 31 Mar 2017   |    35
Thu, 31 Mar 2017   |    45

这就是我想要实现的目标，

的 2017

二月 8 + 0

月 100 + 35 + 45

2016

月 45 + 52 + 23

月 9 + 33

目前我正在这样做，

$sqly = "SELECT DISTINCT RIGHT(date,4) as year FROM logs ORDER BY id DESC;";
$resy = mysql_query($sqly);
while($rowy = mysql_fetch_array($resy))
{
   echo $rowy['year'];
}

结果：

的 2017

的 2016

我不知道如何进一步了解每年的月份，并总算每个月的总数。

Answer 1

此查询应该有效：

SELECT YEAR(STR_TO_DATE(date, '%W, %d %M %Y')) AS year,
       MONTH(STR_TO_DATE(date, '%W, %d %M %Y')) AS month, 
       SUM(cost) 
FROM logs 
GROUP BY year, month;

Answer 2

尝试此查询。

SELECT YEAR(date) AS year, MONTH(date) AS month, COUNT(DISTINCT id) FROM logs GROUP BY year, month

Answer 3

You can use below code to find your answer, Hope this will help you

<?php

$sqly = "SELECT DISTINCT RIGHT(date,4) as year FROM logs ORDER BY id DESC;";
$resy = mysql_query($sqly);
while($rowy = mysql_fetch_array($resy))
{
   echo $rowy['year'];

   $sqly2 = "select SUBSTRING(date, 9, 3) as month_name, Group_concat(cost,' + ') as total_cost from logs where RIGHT(date,4) = '".$rowy['year']."' GROUP BY SUBSTRING(date, 9, 3)";
    $resy2 = mysql_query($sqly2);

    while($rowy2 = mysql_fetch_array($resy2))
{
   echo $rowy2['month_name'] ." ".$rowy2['total_cost'] ;

}
}