Question

我有一个字符串数组如何比当前更好地定义它？它对我有用，但看起来很奇怪。

var arrTimelineEntry = ["12 am", "1 am", "2 am", "3 am", "4 am", "5 am", "6 am", "7 am","8 am", "9 am", "10 am", "11 am","12 pm", "1 pm", "2 pm", "3 pm", "4 pm", "5 pm", "6 pm", "7 pm", "8 pm", "9 pm", "10 pm", "11 pm"]

Answer 1

以下格式化程序适用于不同的语言环境和语言。

let calendar = Calendar.current
let date = Date() //choose date on which DST never happened

let formatter = DateFormatter()
    formatter.dateFormat = DateFormatter.dateFormat(fromTemplate: "jm", options: 0, locale: NSLocale.current)

let dates = (0...23).map { (hour) in
    return calendar.date(bySettingHour: hour, minute: 0, second: 0, of: date)!
}

let timeLine = dates.map(formatter.string)

Answer 2

可能您可以使用extension的{{1}}来获取这样的全天工作时间。您也可以根据特定要求轻松定制它们，并且它们不是硬编码的。

Date

}

用法：

extension Date {
var startOfDay: Date {
    return Calendar.current.startOfDay(for: self)
}

static func dayHours() -> [String] {
    var hours = [String]()
    var today = Date(timeIntervalSince1970: 1492674841).startOfDay

    let dateFormatter = DateFormatter()
    dateFormatter.locale = NSLocale.current
    dateFormatter.dateFormat = "h a"
    dateFormatter.amSymbol = "am"
    dateFormatter.pmSymbol = "pm"

    for _ in 0...23 {
        let dateString = dateFormatter.string(from: today )
        hours.append(dateString)
        today.addTimeInterval(3600)
    }

    return hours
}

为时间轴定义数组的更好方法，可以更通用

2 个答案: