Question

我有这样的JSON：

{
  "dcsId": "1184001100000000517",
  "marketCode": "US",
  "languageCode": "en-US",
  "profile": {
  "base": {
     "username": "arunima27",
     "activeInd": "R",
     "phone": [
       {
          "activeInd": "Y",
          "type": "mobile",
          "primaryInd": "Y",
          "number": "2234566788"
       },
       {
         "activeInd": "N",
         "type": "mobile",
         "primaryInd": "N",
         "number": ""
       }
      ]
    }
  }
 }

从这个输入JSON我们需要提取payload.profile.base.phone.number，其中payload.profile.base.phone.type ==“mobile”和payload.profile.base.phone.activeInd ==“ Y”。实际上我们需要循环遍历JSON数组（payload.profile.base。* phone）并仅获取活动且类别/类型为移动的电话号码。

我们需要如下输出：

{
  "dcsId": "1184001100000000517",
  "marketCode": "US",
  "languageCode": "en-US",
  "username" :  "arunima27", 
  "phoneNumber" : "2234566788"
}

我们在为“phoneNumber”输出变量进行此转换时遇到问题。

Answer 1

从您的预期结果看起来您只想要第一个匹配的数字。这是数据编织正是这样做的：

%dw 1.0
%output application/json
---
{
    dcsid: payload.dcsId,
    markCode: payload.marketCode,
    languageCode: payload.languageCode,
    username: payload.profile.base.username,
    phoneNumber: (payload.profile.base.phone filter ($.activeInd == 'Y' and $.type == 'mobile'))[0].number
}

如果您想要所有匹配的电话号码，只需离开[0]，结果中的phoneNumber值将是一个数组（而不仅仅是第一个匹配的电话号码）。

Answer 2

这解决了这个问题。

{（payload.profile.base.phone filter（$ .activeInd ==＆＃34; Y＆＃34; and $ .primaryInd ==＆＃34; Y＆＃34;））}。number default＆＃34 ;＆＃34;

Answer 3

在手机上使用过滤器和地图，以达到理想的效果。

phoneNumber: {
    (payload.profile.base.phone filter ($.activeInd == "Y" and $.type == "mobile") map {
        number: $.number
    }
)}

<强>输出

"phoneNumber": {
    "number": "2234566788",
 }

Answer 4

 %dw 2.0
 output application/json
 ---
 payload.profile.base.phone filter ((obj, index) -> (obj.activeInd == 'Y' and obj.type  ~= 'mobile'   ))

如何在Mule DataWeave

4 个答案: