List<Filter> filters;
List<Deal> deals;
using (DealDataContext db = new DealDataContext())
{
XElement xmlTree = XElement.Parse("<Request><ZipCode>92618</ZipCode></Request>");
var result = db.SearchDeals(xmlTree);
filters = result.GetResult<Filter>().ToList();
deals = result.GetResult<Deal>().ToList();
}
return filters, deals;
返回多个对象的最佳方法是什么?
答案 0 :(得分:4)
为ViewModel创建best practices外观。你的情况 -
public class DealViewModel
{
List<Filter> filters{get; set;}
List<Deal> deals{get; set;}
}
功能 -
DealViewModel vm= new DeakViewModel();
using (DealDataContext db = new DealDataContext())
{
XElement xmlTree = XElement.Parse("<Request><ZipCode>92618</ZipCode></Request>");
var result = db.SearchDeals(xmlTree);
vm.filters = result.GetResult<Filter>().ToList();
vm.deals = result.GetResult<Deal>().ToList();
return vm;
}
答案 1 :(得分:1)
创建一个将两个对象包装成一个的类。然后返回你的包装器对象。
public class Wrapper
{
List<Filter> Filters { get; set; }
List<Deal> Deals { get; set; }
}