Question

如何从static void Main() { string[] input = new string[2]; Write("\n Type a room length in feet >> "); input[0] = ReadLine(); Write("\n Type a room width in feet >> "); input[1] = ReadLine(); int endEstimate = PaintJobCalc(input); WriteLine("\n Your Paint Job total will be ${0}", endEstimate); ReadLine(); }元组列表中识别缺少的日期？

例如，如何识别以下列表中的缺失日期：

(start_date, end_date)

以上示例包含以下缺失日期：

dates = [('2011-01-01', '2011-01-14'), ('2011-01-15','2011-01-31'), ('2011-02-01', '2011-02-14'), ('2011-03-01', '2011-03-14'), ('2011-03-16', '2011-03-31')]至2011-02-15
2011-02-28

如何从开始和结束日期元组列表中识别所有缺失的日期？

Answer 1

更加面向对象的解决方案：

from functools import total_ordering
from datetime import timedelta, datetime


@total_ordering
class DateRange(object):
    def __init__(self, start, end):
        assert start <= end
        self.start = start
        self.end = end

    def __contains__(self, other):
        return self.start <= other and self.end >= other

    def __lt__(self, other):
        if self.start == other.start:
            return self.end < other.end
        return self.start < other.start

    def __eq__(self, other):
        return self.start == other.start and self.end == other.end

    def __str__(self):
        return '<%s, %s>' % (self.start.strftime('%Y-%m-%d'), self.end.strftime('%Y-%m-%d'))

    def __iter__(self):
        class DateIterator(object):
            def __init__(self, start, end):
                self.current = start
                self.end = end

            def next(self):
                if self.current > self.end:
                    raise StopIteration()
                self.current += timedelta(days=1)
                return self.current

        return DateIterator(self.start, self.end)

    __repr__ = __str__

dates = [('2011-01-01', '2011-01-14'), ('2011-01-15','2011-01-31'), ('2011-02-01','2011-02-14'), ('2011-03-01','2011-03-14'), ('2011-03-16','2011-03-31')]
dates = [DateRange(datetime.strptime(start, '%Y-%m-%d'), datetime.strptime(end, '%Y-%m-%d')) for start, end in dates]
dates = sorted(dates)

missing = []

previous = None
for date_range in dates:
    if previous is not None and previous < date_range.start:
        missing.append(DateRange(previous, date_range.start + timedelta(days=-1)))

    previous = date_range.end + timedelta(days=1)

print missing

Answer 2

有点冗长，但你明白了

编辑：稍微清理了一下

from datetime import date, timedelta

dates = [('2011-01-01', '2011-01-14'), ('2011-01-15','2011-01-31'), 
         ('2011-02-01', '2011-02-14'), ('2011-03-01', '2011-03-14'), 
         ('2011-03-16', '2011-03-31')]

def d_range(d1,d2):
    delta = d2 - d1 #assumes second date is always after first
    return [d1 + timedelta(days=i) for i in range(delta.days + 1)]

my_days = []

#calc the date range between each tuple
for d in dates:

    d1 = datetime.strptime(d[0],'%Y-%m-%d')
    d2 = datetime.strptime(d[1],'%Y-%m-%d')

    my_days.extend(d_range(d1,d2))


#now do the same for the max and min dates
my_range = d_range(min(my_days), max(my_days))


missing_dates = set(my_range).difference(set(my_days))

并发表您的意见：

missing_dates_list = list(missing_dates)

或回到原始格式：

missing_dates_str =  [datetime.strftime(date, '%Y-%m-%d') for date in missing_dates]

如何从开始和结束日期列表中识别缺失的天数？

2 个答案: